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bulgar
1 month ago
12

How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?

Physics
1 answer:
kicyunya [3.2K]1 month ago
3 0

This problem can be solved using Ampere’s Law:

<span>Bh = μoNI </span>

In this equation:

B = Magnetic Field

h = length of the coil

<span>μo = permeability = 4π*10^-7 T·m/A</span>

N = number of coil turns

I = current

Given values are B = 0.0015T, I = 1.0A, h = 10 cm = 0.1m<span>

Utilizing Ampere's law to determine the number of turns:
This can be rearranged to:
<span>N = Bh/μoI</span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4

</span>

<span>Final answer: 119.4 turns</span>

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