The appropriate conversion should be 0.2. If that's incorrect, please let me know.
Initially, we convert the given radius of the wheel into meters, resulting in 0.325 m. Next, we compute the circumference.
C = 2πrr
By inserting the values,
C = 2π(0.325 m) = 2.04 m
Given a distance of 40 m for the road, we calculate the total number of complete revolutions as follows:
n = 40/2.04 m = 20.
Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Typically, the graph will have a labeled line such as f(x) = ... To find f(3), identify 3 on the x-axis, then trace vertically to the graph line and read the corresponding y-value.
<span>With AB tangent at D, where AD = OD = 4
, triangle OAD forms a right angle with sides measuring 4 and 4.
So, the area of triangle OAD is computed as 1/2 * 4 * 4 = 8
The angles AOD and DAO equal 45 degrees.
Therefore, the area of circular sector OCD is calculated as the area of circle O multiplied by 45/360
= pi * 4 * 4 * 45/360
= 2pi
The shaded area ACD results from the triangle OAD minus the area of circular sector OCD
= 8 - 2pi
= 1.72
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