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ch4aika
3 days ago
7

Air traffic controller Seymour Plains must quickly calculate the altitude of an incoming jet. He records the jet’s angle of elev

ation as 8°. The jet signals that its land (horizontal) distance from the control tower is 74 km. Calculate the altitude of the jet to the nearest meter

Mathematics
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Mia paints interior walls at a rate of 12 m^2/h. At what rate does she paint in cm^2/min?
Inessa [12570]
12 m^2/h to cm^2/min

12 m^2/h × 1 h/60 min = 0.2 m^2/min

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2000 cm^2/min
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Write the standard form of the line that contains a slope of -3/8 and passes through the point (5, -4). Include your work in you
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Which are the roots of the quadratic function f(b) = b2 – 75? Select two options. b = 5 StartRoot 3 EndRoot b = Negative 5 Start
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b = 5√3

b = -5√3

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f(b)=b^{2}-75

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In this case

The roots of the equation are the b values for which f(b) equals zero.

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b=(+/-)\sqrt{75}

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Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Svet_ta [12734]

Response:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Detailed explanation:

In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:

Given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Applying the Poisson process, we find that

(a) at most 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) exactly 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) more than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) exactly 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) within the range of 10 to 15, inclusive

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
2 months ago
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