Which point is a solution to the linear inequality y < Negative one-halfx + 2? (2, 3) (2, 1) (3, –2) (–1, 3)

To properly complete the square, divide the b value by 2 and then square that result. For instance, if b equals 4, you would first halve it to get 2, and the square of 2 would give a result of 4.