Response:
It is inferred that the authors of the sonnets belong to a certain poet from the Elizabethan era.
Step-by-step breakdown:
The details provided in the question are as follows:
Population mean, μ = 8.9
Sample mean,
= 10.2
Sample size, n = 6
Alpha, α = 0.05
Population standard deviation, σ = 2.5
Initially, we formulate the null hypothesis and the alternative hypothesis
To conduct this test, we utilize the One-tailed z test.
a) Equation:
By substituting in all relevant values, we determine:
Next,
b) The p-value is computed using the z-table.
P-value = 0.1003
The p-value surpasses the alpha of 0.05
c) Because the p-value exceeds the alpha threshold, there is insufficient evidence to dismiss the null hypothesis, thereby supporting the null hypothesis.
Consequently, it is concluded that the authorship of the sonnets belongs to a particular Elizabethan poet.
Response: The accurate statements include:-
There are nearly equal quantities of points located above and below the x-axis.
The points are distributed haphazardly without a distinct pattern.
The total number of points matches that of the scatter plot.
Explanation:
- A residual plot illustrates residuals on the vertical axis against the independent variable on the horizontal axis.
Consequently, the count of points is on par with the scatter plot, and roughly the same amount of points exist above and below the x-axis.
Given the random distribution of the points throughout the plot, it signifies there is no correlation, therefore, the points are scattered randomly without a clear arrangement.
We start with the following information:
p = probability = 0.12<span>
n = total number of students = 39 </span>
x = number of left-handers = 5<span>
u = mean = p * n = 4.68
σ = standard deviation = √(n*p*(1-p)) = √(39 * 0.12 * 0.88) =
2.03</span>
Finding the z score:
z = (x – u) / σ
<span>
z = (5 – 4.68) / 2.03
</span>
z
= 0.1576 = 0.16
<span>
</span>Applying standard tables for z gives the p value as:
p value = 0.5636 = 56.36%
Consequently, there is a 56.36% probability.