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Alexxandr
19 days ago
6

Deal with these relations on the set of real numbers: R₁ = {(a, b) ∈ R² | a > b}, the "greater than" relation, R₂ = {(a, b) ∈

R² | a ≥ b}, the "greater than or equal to" relation, R₃ = {(a, b) ∈ R² | a < b}, the "less than" relation, R₄ = {(a, b) ∈ R² | a ≤ b}, the "less than or equal to" relation, R₅ = {(a, b) ∈ R² | a = b}, the "equal to" relation, R₆ = {(a, b) ∈ R² | a ≠ b}, the "unequal to" relation. Find
a)R1◦R1.b)R1◦R2.c)R1◦R3.d)R1◦R4.e)R1◦R5.f)R1◦R6.g)R2◦R3.h)R3◦R3.
Mathematics
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One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are times the
Svet_ta [12734]
T<span>he area of a figure signifies the measure of space within a two-dimensional shape, typically expressed as square units based on the figure's dimensions.

For instance, with a shape having dimensions of k, its area can be given by k^2.
</span>
<span>Consider that one similar figure possesses an area nine times that of another.

As these figures are similar, their areas correspond to the proportionality of their dimensions.

Let the smaller shape's dimensions be k, while the larger is p times the dimensions of the smaller shape. The smaller shape's area is k^2 and the larger shape's area is (pk)^2.

Now, knowing the larger figure's area is nine times the area of the smaller figure, we have:
\frac{(pk)^2}{k^2} = \frac{9}{1} \\ \\ \frac{p^2k^2}{k^2} =9 \\ \\ p^2=9 \\ \\ p= \sqrt{9} \\ \\ p=3
</span>
Thus, the dimensions of the larger figure must be 3 times those of the smaller figure.
3 0
2 months ago
Read 2 more answers
A statistics professor at a large university hypothesizes that students who take statistics in the morning typically do better t
Svet_ta [12734]

Answer:

The resulting value is 2.381

Step-by-step explanation:

Using the information presented in the question, we will calculate the evidence supporting the professor's hypothesis

Given that:

x₁ = 74,

n₁ = 36

s₁ = 8

x₂ = 68

n₂ = 36

s₂ = 10

The hypotheses can be outlined as:

The critical value is t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀₁

thus,

t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀ = 2.381

This implies a range of -2.381 to 2.381

Thus, we can support the professor's assertion.

5 0
2 months ago
Which of the following are exterior angles? Check all that apply.
Svet_ta [12734]

Answer:

A. C. E. F.

Which correspond to 2, 3, 5, and 6.

Step-by-step explanation:

Within geometry, exterior angles are defined as those angles formed between any side of a polygon and the extension of an adjacent side, as demonstrated in the diagram.

Observing the figure, angles 2 and 3 arise from a side of the triangle and a line extended from the following side. Likewise, angles 5 and 6 are created similarly. Thus, these four angles are classified as exterior angles.

8 0
4 months ago
Read 2 more answers
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