tickets were sold at four different gates. Gate D sold 24%. Gate A sold 36%. Gate C sold 14%. Gate B sold 26%. If 39 tickets wer

Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =

AnnZ [12381]

Answer:

The distance from the point (0,1,1) to the specified line is zero.

Step-by-step explanation:

Considering the parametric equations of the line,

x=2t, y=5-2t, z=1+t

In order to calculate the distance from (0,1,1), we must remove t from the equations above, such that

$y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x$

$\implies 3x+2y-2z-8=0\hfill (1)$

whose direction ratios are (l,m,n)=(3,2,-2) and the distance from point (a,b,c)=(0,1,1) is defined as

$\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0$

The distance between the point (0,1,1) and (1) amounts to zero. Therefore, the point (0,1,1) is located on the line (1).

8 0

3 months ago

We can calculate EE, the amount of euros that has the same value as DD U.S. dollars, using the equation E=\dfrac{17}{20}DE=

Leona [12618]

Response:

The equation provided is e=\frac{17}{20}d, where e represents euros and d denotes the equivalent value in U.S. Dollars.

We aim to determine the number of euros for 1 U.S. Dollar.

Substituting d=1 in the above equation

results in

e=\frac{17}{20}(1)

Simplifying gives us

e=\frac{17}{20}

By dividing 17 by 20, we get 0.85.

Thus, 0.85 euros are equivalent to 1 U.S. Dollar.

Read more on -

Step-by-step explanation:

5 0

3 months ago

Read 2 more answers

Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation

Zina [12379]

Answer:

There is a probability of 24.51% that the weight of a bag exceeds the maximum permitted weight of 50 pounds.

Step-by-step explanation:

Problems dealing with normally distributed samples can be addressed using the z-score formula.

For a set with the mean $\mu$ and a standard deviation $\sigma$ , the z-score for a measure X is calculated by

$Z = \frac{X - \mu}{\sigma}$

Once the Z-score is determined, we consult the z-score table to find the related p-value for this score. The p-value signifies the likelihood that the measured value is less than X. Since all probabilities total 1, calculating 1 minus the p-value gives us the probability that the measure exceeds X.

For this case

Imagine the weights of passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, thus $\mu = 47.88, \sigma = 3.09$

What probability exists that a bag’s weight will surpass the maximum allowable of 50 pounds?

That translates to $P(X > 50)$

Thus

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 47.88}{3.09}$

$Z = 0.69$

$Z = 0.69$ has a p-value of 0.7549.

<pthis indicates="" that="" src="https://tex.z-dn.net/?f=P%28X%20%5Cleq%2050%29%20%3D%200.7549" id="TexFormula10" title="P(X \leq 50) = 0.7549" alt="P(X \leq 50) = 0.7549" align="absmiddle" class="latex-formula">.

Additionally, we have that

$P(X \leq 50) + P(X > 50) = 1$

$P(X > 50) = 1 - 0.7549 = 0.2451$

There is a probability of 24.51% that the weight of a bag will exceed the maximum allowable weight of 50 pounds.

</pthis>

6 0

3 months ago

The vertex of this parabola is at (-2, -3). When the y-value is -2, the x-value is -5. Determine the coefficient of the squared

Inessa [12570]

The task requires calculating the coefficient of the squared term in the parabolic equation, and based on my calculations and analysis, I found that the vertex of the parabola can be expressed as y =a(x-h)^2+k, leading me to a simplification that results in x^2.

6 0

2 months ago