Answer:
The system's energy amounts to 15 J.
Explanation:
Given that,
Energy E = 2.5 J
Amplitude = 10 cm
The spring constant needs to be computed.
Using the formula for the mechanical energy of the system,
Substituting the values into the formula:
If the block is swapped out for one with double the original mass,
Amplitude = 6 cm
We need to find the energy
Using the mechanical energy formula,
Substituting into the formula:
Thus, the system’s energy is 15 J.
Response:
Clarification:
The force between two charges, q₁ and q₂ at a distance d is represented by the formula
F = k q₁ q₂ / d²
Here, the force between charge q₁ = -15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C with distance d = (1.66 - 1.24) = 0.42 mm
k = 1 / (4π x 8.85 x 10⁻¹²)
Substituting the values into the equation
F = 1 / (4π x 8.85 x 10⁻¹²) x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 35969.4 x 10⁻³ N.
For the force between charge q₂ = 34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C at a distance d = (1.24 - 0) = 1.24 mm.
Substituting the values into the expression
F = 1 / (4π x 8.85 x 10⁻¹²) x 34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 82729.6 x 10⁻³ N
Both forces direct towards the left (away from the origin, towards the negative x-axis)
Total force = 118699 x 10⁻³
= 118.7 N.
