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slavikrds
3 months ago
7

A 7.0-kilogram cart, A, and a 3.0-kilogram cart, B, are initially held together at rest on a horizontal, frictionless surface. W

hen a compressed spring attached to one of the carts is released, the carts are pushed apart. After the spring is released, the speed of cart B is 6.0 meters per second, as represented in the diagram belowWhat is the speed of cart A after the spring is released?
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
7 0
To address this scenario, we apply the principle of momentum conservation. Given that momentum equals mass multiplied by velocity, we have:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ represent the initial velocities of carts A and B,
v₁' and v₂' denote the final velocities of the respective carts,
and m₁ and m₂ are their masses.

(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁', we find that
v₁' = -2.57 m/s

Consequently, cart A moves at 2.57 m/s in the opposite direction of cart B.
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