answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vesna_86
17 days ago
6

A solution is prepared by dissolving 10.0 g of NaBr and 10.0 g of Na2SO4 in water to make a 100.0 mL solution. This solution is

then mixed with 75.0 mL of a 0.800 M aqueous solution of AlBr3. Calculate the concentration (M) of Na+ and Br− in the final solution.
Chemistry
You might be interested in
A mixture of gases A2 and B2 are introduced to a slender metal cylinder that has one end closed and the other fitted with a pist
eduard [2782]

Response:

q < 0, w > 0, the sign of ΔE cannot be ascertained from the provided details

Explanation:

Assessing the sign of q

The water bath's temperature before the reaction is at 25 °C

Following the reaction, the water bath's temperature rises to 28 °C, suggesting that heat was released from the system during the reaction.

If heat is absorbed by the system, q is positive; if heat is released, q is negative, leading to the conclusion that q < 0 in this scenario.

Determining the sign of w

The downward movement of the piston indicates a reduction in the system's volume, meaning work was conducted on the system. When work is done on the system, w is considered positive; hence, w > 0 in this case.

Evaluating ΔE sign

According to the first law of thermodynamics, the relationship among ΔE, q, and w is represented as follows:

ΔE = q + w

In this instance, since q is negative and w is positive, the resulting sign of ΔE is determined by the relative magnitudes of q and w. Since we lack sufficient information to gauge these magnitudes, we cannot definitively determine the sign of ΔE based on the given data.

As a result, the correct option among the choices presented is c: q < 0, w > 0, the sign of ΔE cannot be discerned from the information given.

3 0
2 months ago
In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay
lorasvet [2795]

Answer:

1984

Explanation:

Utilizing the equation;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half-life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity at time = t

Substituting values, we have 0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

<pthis indicates="" that="" the="" wine="" was="" made="" years="" ago="" which="" corresponds="" to="" year=""> </pthis>
7 0
3 months ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
castortr0y [3046]

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the 10^5 molecules:16.5 nm\times 10^5=16.5\times 10^5 nm

1 nm=10^{-6} mm

The overall width of a crystal measured in millimeters=16.5\times 10^5\times 10^{-6} mm=1.65 mm

The overall width of a crystal is 1.65 mm.

7 0
4 months ago
Read 2 more answers
An experimenter studying the oxidation of fatty acids in extracts of liver found that when palmitate (16:0) was provided as subs
eduard [2782]

Answer:

Fatty acids with an even number of carbons, like palmitate, undergo complete β-oxidation in the liver mitochondria, resulting in CO₂, as acetyl-CoA, their end product, can enter the TCA cycle.

On the other hand, odd-number fatty acids such as undecanoic acid generate acetyl-CoA and propionyl-CoA during their final pass. To allow entry into the TCA cycle, propionyl-CoA must go through additional processes, including carboxylation.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is facilitated by propionyl-CoA carboxylase, a biotin-dependent enzyme that is inhibited by avidin. In contrast, the oxidation of palmitate does not require carboxylation.

Explanation:

Fatty acids with an even number of carbons, such as palmitate, are completely oxidized to CO₂ in the liver mitochondria due to the ability of their oxidation product, acetyl-CoA, to enter the TCA cycle where it is further oxidized to CO₂.

Undecanoic acid is classified as an odd-number fatty acid, consisting of 11 carbon atoms. The last stage of β-oxidation for odd-number fatty acids, like undecanoic acid, produces a five-carbon fatty acyl substrate that is oxidized and split into acetyl-CoA and propionyl-CoA. To enter the TCA cycle, propionyl-CoA needs additional reactions such as carboxylation. Since the oxidation occurs using a liver extract, CO₂ must be supplied externally for propionyl-CoA carboxylation, enabling the complete oxidation of undecanoic acid.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, which contains biotin. The function of biotin is to activate CO₂ before it is transferred to the propionate group. The addition of avidin obstructs the complete oxidation of undecanoic acid as it binds very tightly to biotin, thereby hindering the activation and transfer of CO₂ to propionate.

In contrast, palmitate oxidation does not require carboxylation, meaning that the presence of avidin doesn't influence its oxidation.

6 0
2 months ago
Other questions:
  • During the lab, you will have access to a range of acids and bases as well as universal pH indicator paper. Think about how you
    10·2 answers
  • what does the number of the places after the decimal in a measurement tell you about the precision of the instrument that record
    8·1 answer
  • A crystal of graphite contains which type of bond?
    13·2 answers
  • When the following equation is balanced, the coefficients are __________. Al(NO3)3 + Na2S → Al2S3 + Na(NO3)
    11·1 answer
  • What is the number of moles in 15.0 g AsH3?
    11·1 answer
  • The density of gold is 19.3 g/ml. what is the volume of a gold nugget that weighs 93.5 g?
    15·2 answers
  • Which gas would you expect to deviate more from ideality, h2 or hbr? explain your answer. which factor is the major cause for de
    7·2 answers
  • Why is the first jar of hydrogen gas collected during preparation discarded
    10·2 answers
  • Why is it harder to remove an electron from fluorine than from carbon, or, to put it another way, why are the valence electrons
    15·1 answer
  • Sodium is more reactive than magnesium. true or false
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!