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1 month ago

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is

Chemistry

2 answers:

Tems11 [2.7K]1 month ago

7 0

1.65 mm

Further explanation

Given:

A crystallographer observes horizontal spacing among molecules in a crystal, measuring 16.5 nm.

Question:

What is the entire width of a crystal in millimeters accounting for 10⁵ molecules?

The Process:

A conversion of units is necessary here, focusing on length. We will convert nanometers to millimeters this time.

Recall that,

$\boxed{ \ 1 \ nm = 10^{-9} \ m \ }$

$\boxed{ \ 1 \ mm = 10^{-3} \ m \ }$

Crystallographers have identified 10⁵ molecules across with the inter-molecular gap in the crystal at 16.5 nm.

$\boxed{ \ 10^5 \ molecules \times \frac{16.5 \ nm}{molecules} \times \frac{10^{-9} \ m}{1 \ nm} \times \frac{1 \ mm}{10^{-3} \ m} =? \ }$

We cancel out matching units.

$\boxed{ \ = 10^5 \times 16.5 \times 10^{-9} \times \frac{1 \ mm}{10^{-3}} \ }$

$\boxed{ \ = 16.5 \times 10^{5 - 9 + 3} \ mm \ }$

$\boxed{ \ = 16.5 \times 10^{-1} \ mm \ }$

$\boxed{ \ = \frac{165}{10} \times \frac{1}{10} \ mm \ }$

$\boxed{ \ = \frac{165}{100} \ mm \ } \rightarrow \boxed{\boxed{ \ 1.65 \ mm \ }}$

Consequently, the overall width of a crystal in millimeters is 1.65 mm.

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Keywords: crystallographer, measures, the horizontal spacing, between, molecules, in a crystal, 16.5 nm, the total width, a crystal, in millimeters, nanometers, 10^5 molecules across, write, your answer, as a decimal, conversion, the unit of length, 1.65

castortr0y [3K]1 month ago

7 0

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the $10^5$ molecules: $16.5 nm\times 10^5=16.5\times 10^5 nm$

$1 nm=10^{-6} mm$

The overall width of a crystal measured in millimeters= $16.5\times 10^5\times 10^{-6} mm=1.65 mm$

The overall width of a crystal is 1.65 mm.

Response:

702 mL

To elaborate:

Given the following:

Mass of sodium hydroxide = 13.20 g

Molarity of H₂SO₄ = 0.235 M

We're tasked with finding the volume of acid necessary to neutralize the sodium hydroxide solution

Step 1: Write the balanced reaction equation

The reaction between H₂SO₄ and NaOH can be summarized as follows:

2NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2H₂O(l)

Step 2: Calculate the moles of NaOH

Moles are calculated by dividing mass by molar mass

The molar mass of NaOH is 40.0 g/mol

Hence;

Number of moles of NaOH = 13.20 g ÷ 40 g/mol

= 0.33 moles of NaOH

Step 3: Determine moles of H₂SO₄ that react

According to the balanced equation, 2 moles of NaOH react with 1 mole of H₂SO₄

Therefore, the ratio giving moles of H₂SO₄ = Moles of NaOH ÷ 2

= 0.33 moles ÷ 2

= 0.165 moles

Step 4: Find the volume of H₂SO₄

Molarity indicates the concentration of the solution in moles per liter

Molarity = Moles ÷ Volume

By rearranging the formula, we find volume = Moles ÷ Molarity

= 0.165 moles ÷ 0.235 M

= 0.702 L

= 702 mL

Thus, the volume of the 0.235 M H₂SO₄ acid solution required equals 702 mL

8 0

22 days ago

Three substances are poured in a cylinder with different densities. Draw the cylinder with the three layers and identify the sub

lorasvet [2795]

Clarification:

hrydhdhdhfhjfhfufufu

3 0

1 month ago

Challenge Problem: An aqueous solution contains 167 g CuSO4 in 820 mL of solution. The density of the solution is 1.195 g/mL. Ca

lorasvet [2795]

Responses: a. 1.28 mol/L; b. 17.0 %; c. 0.0227; d. 1.29 mol/kg Explanation: a. Molar concentration: c = moles/litres. Moles = 167 × 1/159.61. After performing the calculation, Moles = 1.046 mol. Litres = 820 × 1/1000. Hence, Litres = 0.8200 L. Calculating the molar concentration gives c = 1.046/0.8200, resulting in c = 1.28 mol·L⁻¹. b. Percent by mass: Mass % = mass of solute / mass of solution × 100 %. Mass of solution = volume × density, therefore, Mass of solution = 820 × 1.195. By calculating this, Mass of solution = 979.9 g. Thus, Mass % = 167/979.9 × 100, which results in Mass % = 17.0 %. c. Mole fraction: χ = moles of solute / (moles of solvent + moles of solute). Mass of solvent = mass of solution – mass of solute; namely, Mass of solvent = 979.9 – 167. Converting this to moles gives Moles of water = 812.9 × 1/18.02, which results in Moles of water = 45.11 mol. The total moles are 1.046 + 45.11, leading to Total moles = 46.16 mol. Finally, the mole fraction is calculated as χ = 1.046/46.16, equating to χ = 0.0227. d. Molal concentration: b = moles of solute / kilograms of solvent. Mass of solvent = 812.9 g = 0.8129 kg. Therefore, the molal concentration yields: b = 1.046/0.8129 = 1.29 mol/kg.

5 0

18 days ago

How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?

lions [2927]

I believe you mean KO2 reacting with H2O. The reaction is 4KO2+2H2O->4KOH +3O2. The mole ratio O2:KO2 is 3:4. Thus moles of O2 produced = 0.500/4*3 = 0.375 mol.

6 0

20 days ago

A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w

Anarel [2989]

Answer:

The glycerol solution has a molality of 2.960×10^-2 mol/kg.

Explanation:

Calculating the moles of glycerol involves the formula: Moles = Molarity × Volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles.

To find the mass of water, use: Mass = Density × Volume = 0.9982 g/mL × 998.7 mL = 996.90 g, which converts to 0.9969 kg.

The formula for molality is: Molality = Moles of solute/Mass of solvent (in kg) = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg.

7 0

1 month ago