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MaRussiya
11 days ago
8

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is

Chemistry
2 answers:
Tems11 [846]11 days ago
7 0

1.65 mm

Further explanation

Given:

A crystallographer observes horizontal spacing among molecules in a crystal, measuring 16.5 nm.

Question:

What is the entire width of a crystal in millimeters accounting for 10⁵ molecules?

The Process:

A conversion of units is necessary here, focusing on length. We will convert nanometers to millimeters this time.

Recall that,

\boxed{ \ 1 \ nm = 10^{-9} \ m \ }

\boxed{ \ 1 \ mm = 10^{-3} \ m \ }

Crystallographers have identified 10⁵ molecules across with the inter-molecular gap in the crystal at 16.5 nm.

\boxed{ \ 10^5 \ molecules \times \frac{16.5 \ nm}{molecules} \times \frac{10^{-9} \ m}{1 \ nm} \times \frac{1 \ mm}{10^{-3} \ m} =? \ }

We cancel out matching units.

\boxed{ \ = 10^5 \times 16.5 \times 10^{-9} \times \frac{1 \ mm}{10^{-3}} \ }

\boxed{ \ = 16.5 \times 10^{5 - 9 + 3} \ mm \ }

\boxed{ \ = 16.5 \times 10^{-1} \ mm \ }

\boxed{ \ = \frac{165}{10} \times \frac{1}{10} \ mm \ }

\boxed{ \ = \frac{165}{100} \ mm \ } \rightarrow \boxed{\boxed{ \ 1.65 \ mm \ }}

Consequently, the overall width of a crystal in millimeters is 1.65 mm.

Learn more

  1. What is the speed in km/hr and mi/min (miles/minute)?
  2. How many milliliters of coffee were in each cup?
  3. Convert the hippopotamus's weight to kilograms

Keywords: crystallographer, measures, the horizontal spacing, between, molecules, in a crystal, 16.5 nm, the total width, a crystal, in millimeters, nanometers, 10^5 molecules across, write, your answer, as a decimal, conversion, the unit of length, 1.65

castortr0y [923]11 days ago
7 0

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the 10^5 molecules:16.5 nm\times 10^5=16.5\times 10^5 nm

1 nm=10^{-6} mm

The overall width of a crystal measured in millimeters=16.5\times 10^5\times 10^{-6} mm=1.65 mm

The overall width of a crystal is 1.65 mm.

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The Δ H value for butane (g) is -124.7 kJ/mol.

The Δ H value for CO2 (g) is -393.5 kJ/mol.

The Δ H value for H2O (g) is -241.8 kJ/mol.

The mass of butane is 8.30 grams.

Butane has a molar mass of 58 g/mol.

Considering the reaction,

C₄H₁₀ + 6.5 O₂ = 4CO₂ + 5H₂O

To determine the Δ H° of the reaction:

ΔH°rxn = ∑nH° f (products) - ∑nH° f (reactants)

By substituting values, we find that

Δ H° rxn = 4 (-393.5) + 5 (-241.8) - (-124.7)

= -1574 -1209 + 124.7

= -2783 - 124.7

= -2658.3 kJ/mol

Now, we will calculate how many moles of butane are in 8.30 grams.

Number of moles = mass/molar mass

= 8.30 / 58

= 0.143 moles

Therefore, the total energy released during the reaction is given by,

Q = number of moles × ΔH° rxn

= 0.143 × (2658.3)

= 380.14 kJ

Thus, the total heat released in the reaction is 380.14 kJ.

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You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation
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The L- isomer serves as the enantiomer of the D- isomer, and given that the optical rotation of the D- isomer is + 13.5°, the L- isomer's optical rotation will have the same magnitude but an opposite sign, resulting in -13.5°.

Thus, the rotation of the racemic mixture will be equal to 0°.


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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
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Answer:

The forward reaction will keep occurring until all NO or all NO₂ is consumed.

Clarification:

  • According to Le Châtelier's principle, when a system at equilibrium experiences a disturbance from an outside source, the system will adjust to counteract this disturbance and restore equilibrium.

  • Thus, removing the product (N₂O₃) from the system effectively lowers the product concentration, prompting the reaction to shift forward and generate additional product in order to alleviate the strain caused by the removal of N₂O₃.

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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
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First convert grams of C4H10 to moles using its molar mass of 58.1 g/mol: 3.50 g C4H10 × (1 mol C4H10 / 58.1 g C4H10) = 0.06024 mol C4H10 Next convert moles to molecules using Avogadro’s number: 0.06024 mol C4H10 × (6.022×10^23 molecules C4H10 / 1 mol C4H10) = 3.627×10^22 molecules C4H10 Each butane molecule contains 4 carbon atoms, so: 3.627×10^22 molecules C4H10 × (4 atoms C / 1 molecule C4H10) = 1.45×10^23 carbon atoms present.
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Response:

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