The density of gold is 19.3 g/ml. what is the volume of a gold nugget that weighs 93.5 g?

Answer:

The solution to your inquiry is C = 0.000333 kcal/g°C

or C = 0.333 cal/g°C

Explanation:

Data

Q = 1.67 kcal

mass = 79.2 g

ΔT = 63.3°C

Formula

Q = mCΔT

Solving for C

C = Q/mΔT

Substituting values

C = 1.67/(79.2 x 63.3)

Simplifying

C = 1.67 / 5013.4

Final Result

C = 0.000333 kcal/g°C

or C = 0.333 cal/g°C

The percentage of KCl present in the mixture is approximately <span>40%</span><span>If we consider a 100-gram sample of the mixture:ω(K) = 44.20% ÷ 100% = 0.442.
m(K) = 0.442 · 100 g = 44.2 g.</span>n(K) = 44.2 g ÷ 39.1 g/mol.
n(K) = 1.13 mol.
n(KCl) + n(KNO₃) = n(K)
m(KCl) = x.
m(KNO₃) = y.
Two equations:
1) x + y = 100 g.
2) m(KCl)/M(KCl) + m(KNO₃)/M(KNO₃) = 1.13 mol.
x/74.55 g/mol + y/101.1 g/mol = 1.13 mol.
From the first equation, we find x = 100 - y and substitute into the second equation:
(100 - y)/74.55 + y/101.1 = 1.13 /×101.1.
135.61 - 1.356y + y = 114.24.
0.356y = 22.37 g.
y = 62.83 g.
Thus, x = m(KCl) = 100 g - 62.83 g = 37.17 g.

I believe you mean KO2 reacting with H2O. The reaction is 4KO2+2H2O->4KOH +3O2. The mole ratio O2:KO2 is 3:4. Thus moles of O2 produced = 0.500/4*3 = 0.375 mol.

Answer:

For A: The change in free energy for the reaction is -5339.76 J/mol

For B: Free energy change is expressed in kJ/mol

For C: The forward reaction favors progression, while the reverse reaction does not.

Explanation:

Regarding the specified chemical reaction:

• For A:

The relationship between standard Gibbs free energy and equilibrium constant is as follows:

The free energy change can be calculated using the following equation:

Or,

where,

= Change in free energy

R = Gas constant =

= standard temperature =

T = temperature of the cell =

= equilibrium constant =

Q = reaction quotient =

= 0.06 M

[DHAP] = 0.125 M

Substituting the values into the equation yields:

Thus, the change in free energy for the reaction is -5339.76 J/mol

• For B:

To convert the free energy change to kilojoules, we apply the conversion factor:

1 kJ = 1000 J

So,

Consequently, the free energy change's units are kJ/mol

• For C:

For spontaneity in the reaction, the Gibbs free energy must be negative. However, the calculations indicate a positive Gibbs free energy, leading to the conclusion that the reaction is not spontaneous.

The free energy change of the reaction is negative.

Consequently, the forward reaction is favored and the reverse reaction is not favored.

Answer:

Central metal oxidation state: +2

Coordination number: 6

Overall charge: -2

Explanation:

For the ion complex:

Na₂[Cr(NH₃)₂(NCS)₄]

The central metal is chromium, with NH₃ and NCS as the ligands.

NH₃ acts as a neutral ligand, while NCS carries a negative charge.

The entire complex has a charge of:

2Na⁺ +  [Cr(NH₃)₂(NCS)₄]⁻² → -2

Since each NCS contributes -1 and there are four NCS, the Cr must possess an oxidation state of +2 to achieve an overall charge of -2.

With 2 NH₃ and 4 NCS attached, the coordination number sums to 2+4 = 6

I trust this clarifies the matter!