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20 days ago

Evaluate the profit function at each vertex. P = 0.04x + 0.05y + 0.06(16 – x – y) (8, 1) P = (14, 1) P = (3, 6) P = (5, 10) P =

Mathematics

2 answers:

PIT_PIT [9.1K]20 days ago

6 0

Final Result:

A maximum profit of $(840) can be achieved by directing $(3,000) toward stock A, $(6,000) toward stock B, and $(7,000) towards stock C.

THIS IS PART B ON EDGE!!!

Detailed explanation:

Svet_ta [9.5K]20 days ago

3 0

The provided function is:
P = 0.04x + 0.05y + 0.06(16-x-y)

To determine the function's value at each vertex, simply plug in the respective x and y coordinates into the equation to find the value of P as shown below:
1- For (8,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(8) + 0.05(1) + 0.06(16-8-1)
P = 0.79

2- For (14,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(14) + 0.05(1) + 0.06(16-14-1)
P = 0.67

3- For (3,6):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(3) + 0.05(6) + 0.06(16-3-6)
P = 0.84

4- For (5,10):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(5) + 0.05(10) + 0.06(16-5-10)
P = 0.76

I hope this is useful:)

Solution:

We need to write 762,508 using expanded notation with exponents.

Expanded form indicates how to represent numbers to highlight the individual digit values.

Displaying 762508 in Expanded format

Let's determine the positional values of each digit:

The concept of place value signifies the worth assigned to each digit based on its location.

For 7, the place value is 700,000

In 762508, the digit 7 is located in the hundred-thousands position.

For 6, the place value is 60,000

In 762508, the digit 6 occupies the ten-thousands position.

For 2, the place value is 2,000

In 762508, 2 is in the thousands position.

For 5, the place value is 500

In 762508, 5 is placed in the hundreds position.

For 0, the place value is 0 x 10 = 0

In 762508, 0 is found in the tens position.

For 8, the place value is 8

In 762508, 8 is positioned in the units place.

Thus, the expanded form is:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

Expressed with exponents, it can be written as:

$7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0$

6 0

20 days ago

Jack bought 4 dozen eggs at k10 per dozen. 6 eggs were broken .what percent of his money goes waste?

zzz [9080]

Step-by-step explanation:

I hope this meets your requirements.

PLEASE MAKE ME BRAINLIEST

3 0

16 days ago

The Spirit Team will be selling popcorn as a fundraiser at the next basketball game to earn funds to go to Orlando for a competi

zzz [9080]

Response:1 and 2

Step-by-step Explanation:

Provided data

Volume required $V=220\ in.^3$

For the initial cylinder

$r=3\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_1=\pi (3)^2(4)$

$V_1=113.11\ in^3$

For the second cylinder

$r=4\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_2=\pi (4)^2(4)$

$V_2=201.08\ in^3$

For the third cylinder

$r=9\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_3=\pi (9)^2(9)$

$V_3=2290.51\ in^3$

For the fourth cylinder

$r=4\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_4=\pi (4)^2(9)$

$V_4=452.448\ in^3$

Thus, cylinders $1$ and $2$ meet the requirement as they remain under $220\ in.^3$

3 0

1 month ago

Translate to an algebraic expression n−1 increased by 110%

tester [8842]

Answer:

Part 1) The algebraic expression can be represented as $1.10(n-1)$ or $1.10n-1.10$

Part 2) The algebraic expression is represented as $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) The expression (n-1) raised by 110%

Recognizing that

110%=110/100=1.10

thus,

The algebraic representation of (n-1) increased by 110% translates to 1.10 multiplied by (n-1).

$1.10(n-1)$

Expanded

$1.10n-1.10$

Part 2) The expression n^(-1) raised by 110%

<pGiven that

110%=110/100=1.10

therefore, the representation of n^(-1) increased by 110% becomes 1.10 multiplied by n^(-1).

Remember that

$n^{-1}=\frac{1}{n}$

thus,

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$

6 0

1 month ago

A truck with a heavy load drove from Boston to New York at 50 mph. After dropping of the load, it returned from New York to Bost

Zina [9171]

Answer:

175/3 or 58.333...

Step-by-step explanation:

This problem can be complex, but I'll simplify it. I apologize for the challenges involved in formatting fractions correctly. To ensure accuracy, I've added several parentheses that may seem unnecessary.

Let d denote the distance between the two cities.

The time it takes can be expressed as d/r, where r represents the speed; thus, from B to NY, it is d/50.

In the same manner, from NY to B, it's d/70.

The average velocity can be determined as 2d divided by the sum of d/50 and d/70, representing the average time.

Next, eliminate d from the equation to reach (d/d)*2/(1/50+1/70).

Now, you can multiply by the Least Common Multiple (LCM) over itself, which is 350/350.

The result after performing this calculation will yield 700/12, equating to 58.333...(This is how you would enter it into your RSM browser) I hope this clarification is useful. My apologies for the delay.

8 0

29 days ago