How much of a circle does a 100-degree angle turn through?

A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,

Svet_ta [12734]

Answer:

B

Step-by-step explanation:

6 0

2 months ago

Read 2 more answers

Question 1 Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your metho

babunello [11817]

Answer:

(a) The 95% confidence interval representing the percentage of the entire U.S. population that would select American football as their preferred television sport is (0.34, 0.40).

(b) Not reasonable.

Step-by-step explanation:

Given:

n = 1000

$\hat p$ = 0.37

(a)

The confidence interval (1 - α)% for proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Where:

$\hat p$ = the sample proportion

n = sample size

$z_{\alpha/2}$ = critical z value.

Calculate the critical value of z for a 95% confidence level as shown:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Refer to a z-table for the necessary value.

Compute the 95% confidence interval for proportion p as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.37\pm 1.96\times\sqrt{\frac{0.37(1-0.37)}{1000}}$

$=0.37\pm 0.03\\=(0.34, 0.40)$

Thus, the 95% confidence interval indicating the proportion of individuals in the U.S. who might say their preferred sport on TV is American football is (0.34, 0.40).

(b)

Next, we must assess if it's rational to consider that the actual percent of people in the United States who favor American football on television is 33%.

The hypothesis is defined as:

H₀: The portion of the U.S. population claiming American football as their favorite sport on television is 33%, meaning p = 0.33.

Hₐ: The proportion of people in the U.S. whose favorite sport to watch on television is not 33%, or p ≠ 0.33

This hypothesis can be verified using a confidence interval.

The decision rule:

If the (1 - α)% confidence interval contains the null value of the hypothesis, then the null hypothesis is not rejected. If, however, the (1 - α)% confidence interval excludes the null value of the hypothesis, then the null hypothesis is rejected.

The confidence interval does encompass the null value of p, which is 0.33.

<pthus the="" null="" hypothesis="" will="" be="" rejected.=""><pin conclusion="" it="" is="">not reasonable to accept that 33% represents the actual percentage of those in the U.S. whose favorite televised sport is American football.

</pin></pthus></pthe>

6 0

4 months ago

A. Consider the following algorithm segment: for i := 1 to 4, for j := 1 to i, [Statements in body of inner loop. None contain b

tester [12383]

Answer:

(a) 4i iterations

(b) "i × n" iterations

Step-by-step explanation:

(a) The provided algorithm segment shows:

for i:= 1 to 4, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

The inner loop executes i times while the outer loop completes 4 cycles.

The inner loop’s total execution when the full algorithm runs is:

= i × 4

= 4i iterations

(b) In the given algorithm segment;

for i:= 1 to n, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

where n denotes a set of positive integers.

= i × n

= "i × n" iterations

</pthus></pthe>

6 0

3 months ago

A survey of 96 students on campus showed that 29 read the Campus Observer student newspaper that morning, 24 read the news via t

Inessa [12570]

Part 1: (a) The count of individuals reading either the Internet news or the local paper, but not both, totals 25 students. Part 2: (b) There are 3 students who engage with both the Internet news and the local paper, excluding the Campus Observer. Part 3: (c) The figure for those who read either the Internet news or the Campus Observer, or both, is 65 students.

6 0

3 months ago