The probability is 0. Fair dice have six sides, and each side has an equal chance of being rolled. The maximum possible outcome with two dice is 6 + 6 = 12, rendering a total of 13 unattainable. Hence, the probability of achieving a total of 13 is 0.
Response:
Step-by-step breakdown:
For the null hypothesis,
H0: p = 88
For the alternative hypothesis,
Ha: p < 88
In terms of population proportion, where the probability of success is p = 0.88
q represents the probability of failure = 1 - p
q = 1 - 0.88 = 0.12
Considering the sample,
Sample proportion, P = x/n
Where
x = number of successes = 21
n = total samples = 32
P = 21/32 = 0.66
Next, we determine the test statistic, which represents the z-score
z = (P - p)/√pq/n
z = (0.66 - 0.88)/√(0.88 × 0.12)/32 = - 3.83
The relevant p-value corresponds by referencing the normal distribution table for the area falling beneath the z-score. As a result,
P value = 0.00006
