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nalin
10 days ago
13

PLZ HELP ME ASAP The box plot shows the typing speed (in words per minute without errors) of the contestants in a typing contest

.
The interquartile range of team A is
A.3
B.4
C.8
D.9
And the interquartile range of team B is
A.4
B.5
C.8
D.9
The difference of the medians of team A and team B is
A.4
B.7
C.8
D.9
This value is equal to about
A.half
B.1 times
C.2 times
the interquartile range of either data set.

Mathematics
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A car with an initial cost of $23,000 is decreasing in value at a rate of 8% each year. Write the exponential decay function des
tester [12383]

Answer:

Step-by-step explanation:

We will utilize the exponential decay formula described as

A = P(1 - r/n)^(nt)

Where

A symbolizes the value after a time period t.

n refers to the timeframe for value loss calculation

t indicates the number of years.

P stands for the population value.

r indicates the rate of decrease.

Based on the provided data,

P = 23000

r = 8% = 8/100 = 0.08

n = 1

Thus, the exponential decay function fitting this situation is

A = 23000(1 - 0.08/n)^1)^ t

A = 23000(0.92)^t

If A = 15000, it follows that

15000 = 23000(0.92)^t

0.92^t = 15000/23000 = 0.6522

Taking logarithm of both sides to base 10

Log(0.92^t) = log(0.6522)

t log(0.92) = log(0.6522)

- 0.036t = - 0.1856

t = - 0.1856/- 0.036

We find t = 5 years rounded to the nearest year

3 0
2 months ago
PQ⊥PS , m∠QPR=7x−9, m∠RPS=4x+22<br> Find : m∠QPR
zzz [12365]

Given:

It is stated that

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the measure of ∠QPR.

Formula

According to the problem PR sits between PQ and PS,

Consequently,

∠QPR+∠RPS = 90°

Now,

Inserting the values for ∠RPS and ∠QPR yields

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 into ∠QPR gives us

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

So,

The measure of ∠QPR is 40°.

3 0
3 months ago
If a point is chosen inside the large circle, what is the probability that it will also be inside the small circle?
babunello [11817]
If a point is randomly selected within the larger circle, the chance that it also lies within the smaller circle is 0.25. Step-by-step explanation: i) The area of the smaller circle is calculated as \pi \times (1)^2 = \pi

. ii) The area of the larger circle is given by \pi times 2^{2} = 4\pi

. iii) The likelihood that a randomly selected point from the larger circle also resides in the smaller circle is expressed as \frac{\pi}{4\pi} = \frac{1}{4} = 0.25

.
6 0
3 months ago
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