Answer:
Let the train's speed be denoted as x km/h.
Scenario 1:
Distance = 288 km
Speed = x km/h
Time = Distance divided by Speed
= 288/x hours
Scenario 2:
Distance = 288 km
Speed = (x + 4) km/h
Time = 288/(x + 4) hours
As 288/x is greater than 288/(x + 4)
288/x - 288/(x + 4) = 1
288[1/x - 1/(x + 4)] = 1
[x + 4 - x] / [x(x + 4)] = 1/288
[4 / (x^2 + 4x)] = 1/288
x² + 4x = 1152
x² + 4x - 1152 = 0
x² + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0, x - 32 = 0
x = -36, x = 32
x = -36 is not valid as speed cannot be negative.
Conclusively, the train's speed = 32 km/h
The general equation for exponential decay characterized by a half-life (T) is expressed as N(t) = N_0(1/2)^(t/T), where N(t) signifies the amount remaining at time t, N_0 stands for the initial amount (at t=0), and T denotes the half-life of the substance. The half-life of carbon-14 is about 5,730 years. When starting with 6 mg of carbon-14, the equation for the remaining amount after t years would be established.
The response is B: 5 and 5 square root 3.
