What values of b satisfy 4(3b + 2)2 = 64?

1 answer:

8 0

Starting with the equation 4(3b + 2)² = 64, if we divide both sides by 4 we obtain (3b + 2)² = 16. By taking the square root of both sides, we derive two cases: (3b + 2) = 4 and (3b + 2) = -4. Solving each equation for b yields: 3b = 2 or 3b = -6, leading to b values of 2/3 and -2. Ultimately, the results specify that b = 2/3 and b = -2.

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The city planning committee wants one tree planted every 20 ft along Dayton Ave. if the perimeter of the plot of land is 234 ft

lawyer [12517]

Answer: It’s two trees

Step-by-step explanation:

Given that the city plants a tree every 20 feet along Dayton Avenue, we first need to establish the length of the side that faces Dayton Avenue.

We currently have three sides unaccounted for. However, it’s crucial to note that the side next to Dayton Avenue has the same length as the two unaccounted sides combined. This equivalence holds because both lengths include the 1 feather and 2 feather markers, confirming congruence.

Thus, the sum of both side lengths will be $234-52-68=114$ .

Consequently, the side next to Dayton Avenue measures

$114\div2=57$ feet.

Having determined that this side is 57 feet long, we divide this length by 20 to find the tree planting intervals. Since the planting occurs only in complete 20-foot segments, if the division results in a decimal, we must round down. A tree is only planted if complete segments of 20 feet are reached.

$57\div20=2.85$

This rounding process gives us 2.

I hope this clarifies!

3 0

3 months ago

Read 2 more answers

Seventy-five cars sit on a parking lot. Thirty have stereo systems, 30 have air conditioners and 40 have sun roofs. Thirty of th

Inessa [12570]

Response:

a. 55 cars

b. 25 cars

Detailed explanation:

Let’s denote the quantity of cars with stereo systems as N(ss), those with air conditioning as N(ac), and those with sunroofs as N(sr).

We find that:

N(ss) = 30

N(ac) = 30

N(sr) = 40

N(ss and ac and sr) = 15

N(at least two) = 30

To calculate how many cars possess at least one feature (N(at least one) or N(ss or ac or sr)), we apply:

N(ss or ac or sr) = N(ss) + N(ac) + N(sr) - N(ss and ac) - N(ss and sr) - N(ac and sr) + N(ss and ac and sr)

N(ss or ac or sr) = 30 + 30 + 40 - (N(at least two) + 2*N(ss and ac and sr)) + 15

Substituting, we find N(ss or ac or sr) = 30 + 30 + 40 - (30 + 2*15) + 15 = 55

For those cars that have exactly one feature, we have:

N(only one) = N(at least one) - N(at least two)

N(only one) = 55 - 30 = 25

3 0

2 months ago