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motikmotik
2 months ago
6

the vertex form of a function is g(x) = (x – 3)2 9. how does the graph of g(x) compare to the graph of the function f(x) = x2? g

(x) is shifted 3 units left and 9 units up. g(x) is shifted 3 units right and 9 units up. g(x) is shifted 9 units left and 3 units down. g(x) is shifted 9 units right and 3 units down.
Mathematics
2 answers:
Inessa [12.5K]2 months ago
9 0
The vertex of the graph for the function g(x) = (x- 3)^2 + 9 is located 3 units to the right and 9 units upwards compared to the vertex of the function f(x) = x^2.
Zina [12.3K]2 months ago
7 0

Answer:

The vertex for the function g(x) = (x- 3)^2 + 9 is found 3 units to the right and 9 units up from the vertex of f(x) = x^2.

Step-by-step explanation:

The vertex for the function g(x) = (x- 3)^2 + 9 is found 3 units to the right and 9 units up from the vertex of f(x) = x^2.

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[[IMG_1]]

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g(x)=6(3)^x

Step-by-step explanation:

We are provided with the information that

f(x)=6(\frac{1}{3})^x

Function f is decreasing as it moves from quadrant 2 to quadrant 1, tending towards y=0

It intersects the y-axis at the point (0,6) and goes through (1,2).

Function g(x) also approaches y=0 in quadrant 2, but increases in quadrant 1.

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Reflection across y-axis:

The transformation rule is identified as

(x,y)\rightarrow (-x,y)

Applying this rule, we derive

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

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for x=0

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Consequently,g(x)=6(3)^x holds true.

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