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ludmilkaskok
11 days ago
12

A charge q = 2.00 μC is placed at the origin in a region where there is already a uniform electric field = (100 N/C) î. Calculat

e the flux of the net electric field through a Gaussian sphere of radius R = 10.0 cm centered at the origin. (ε0 = 8.85 × 10-12 C2/N ∙ m2)
Physics
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A submarine dives from rest a 100-m distance beneath the surface of an ocean. Initially, the submarine moves at a constant rate
Keith_Richards [3271]
a. Time = 16.11 s b. Gauge Pressure = 1009400 Pa = 1 MPa c. Absolute Pressure = 1110725 Pa + 1.11 MPa d. Force = 2.22 MN
8 0
2 months ago
Rod A and rod B are cylindrical rods made of the same metal. amd they differ only in size. Rod B has double the length and doubl
Keith_Richards [3271]

Answer:

The answer I think fits this question is D.

Explanation:

I hope this is helpful and accurate.

6 0
3 months ago
Read 2 more answers
A particle in the first excited state of a one-dimensional infinite potential energy well (with U = 0 inside the well) has an en
kicyunya [3294]

Answer:

The particle's energy in its ground state is E₁=1.5 eV.

Explanation:

For a particle with mass m in the nth energy level of an infinite square well potential of width L , the energy E_{n} is given by:

                                                    E_{n}=\frac{n^{2}h^{2}}{8mL^{2}}

In the ground state (n=1) and in the first excited state (n=2), where the energy is noted as E₂= 6.0 eV. Substituting into the above equation yields:

                                                    E_{1}=\frac{h^{2}}{8mL^{2}}            

                                                    E_{2}=\frac{h^{2}}{2mL^{2}}

Thus, we can express the ground state's energy as:

                                                   E_{1}=\frac{1}{4}(\frac{h^{2}}{2mL^{2}})

                                                      E_{1}=\frac{1}{4} E_{2}

                                                   E_{1}=\frac{1}{4} ( 6.0\ eV)

Ultimately

                                                    E_{1}=1.5\ eV

                                                   

                                                   

6 0
3 months ago
A particle moves along the x axis according to the equation x = 2.00 + 3.00 t – 1.00 t2, where x is in meters and t is in second
Keith_Richards [3271]
¿Dónde está la respuesta?
8 0
2 months ago
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