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Cerrena
12 days ago
6

What are some issues that governments must consider before passing conservation policies? Check all that apply.

Physics
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4. A cylindrical tube has a length of 14.4cm and a radius of 1.5cm and is filled with a colorless gas. If the density of the gas
serg [3582]
The mass, m, of the gas amounts to 0.2504 grams. Explanation: First, we need to calculate the cylindrical tube's volume. The formula for the volume of a cylinder is given by; where V indicates volume, π signifies pi, r represents the radius, and h indicates height or length. Given the following parameters: Radius, r = 1.5 cm, Length, h = 14.4 cm, Density, d = 0.00123 g/cm³. Plugging these into the equation, the volume of the cylindrical tube calculates to be 203.6016 cm³. Density can be defined as mass divided by the volume of an object. Simply put, density is mass per unit volume. Mathematically, density is represented by the formula; by substituting into the equation, we conclude that Mass = 0.2504 g.
5 0
3 months ago
Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta
ValentinkaMS [3465]

Answer:

The amount of heat that enters the gas throughout this two-step process totals 120 cal.

Explanation:

Given that,

Moles present = 3

Heat capacity at volume held constant = 4.9 cal/mol.K

Heat capacity at pressure held constant = 6.9 cal/mol.K

Starting temperature = 300 K

Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

\Delta H_{1}=nC_{p}\times\Delta T

Substituting the values into the equation

\Delta H_{1}=3\times6.9\times(320-300)

\Delta H_{1}=414\ cal

Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

\Delta H_{1}=nC_{v}\times\Delta T

Insert the values into the formula

\Delta H_{1}=3\times4.9\times(300-320)

\Delta H_{1}=-294\ cal

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

\Delta H_{T}=\Delta H_{1}+\Delta H_{2}

\Delta H_{T}=414-294

\Delta H_{T}=120\ cal

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

7 0
3 months ago
A fox locates rodents under the snow by the slight sounds they make. The fox then leaps straight into the air and burrows its no
Ostrovityanka [3204]

Response:

v = 4.08 m/s²

Clarification:

4 0
3 months ago
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