Thermal Power is approximately 460W. According to the Stephan-Boltzmann Law Formula: P = єσT⁴A, where: P = radiation energy, σ = Stefan-Boltzmann Constant, T = absolute temperature in Kelvin, є = emissivity of the material, and A = the surface area. Given that σ = 5.67 x 10^(-8), ε = 0.6, and T = 30°C which converts to Kelvin as 303K, with the human body dimensions of 2m length and 0.8m circumference leading to an area of 1.6m², so thermal power equals 0.6 x 5.67 x 10^(-8) x 303⁴ x 1.6 = 458.8W. Rounding gives about 460W.
<span>Let F represent the maximum thrust produced by the car's motor. Thus, F = ma = 1300 x 3.0 = 3900 N. After adding the load, F stays the same, leading to the equation F = 1700a, which results in a = F/1700 = 3900/1700 = 2.3 m/s².</span>
The full sentence states:
In a third class lever, the distance between the effort and the fulcrum is LESS than the distance between the load/resistance and the fulcrum.
In a third class lever, the fulcrum is positioned on one end of the effort, while the load/resistance is on the opposite side, placing the effort somewhere in between. Consequently, the distance from the effort to the fulcrum is less than that from the load to the fulcrum.
The answer is
-Small f and large D.
The explanation:
-A car jack acts as a machine, defined as an apparatus that aids individuals in exerting force more easily.
-Hence, by applying a small force to the jack, the height at which the car is elevated increases.
Machines are essential for people to amplify their strength; without them, lifting a car would be impossible.
Employing leverage or hydraulic principles, machines enhance your exerted force.
Utilizing a greater lever allows for extensive movement with minimal force, resulting in the opposite side moving shorter distances with an increased force.
Answer:
The answer to the specified question will be "
".
Explanation:
Referring to the question,
⇒ 
⇒ 
...(equation 1)
⇒ 
⇒ 
...(equation 2)
Now,
From equation 1 and equation 2, we conclude
⇒ 
By substituting the value of 
, we derive
⇒ 
⇒
