18.95(0.3 + 0.1) is the formula to use.
Step-by-step explanation:
I hope this meets your requirements.
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Answer:
qt's length = 16
Step-by-step explanation:
The problem states that qrs is a right triangle,
where qr = 20
sr =?
qs = 25
qt =?
1)
Calculate sr
hypotenuse² = base² + height²
sq² = sr² + rq²
25² - 20² = sr²
sr = √(25² - 20²)
sr = 15
2)
When altitude rt is dropped to hypotenuse qs, it creates
two right triangles: rtq and rts.
Δrtq
height = rt
base= tq = 25 - x
hypotenuse = qt = 20
Δrts
height = rt
base= ts = x
hypotenuse = sr = 15
Both triangles share the same height, which is rt
Using the Pythagorean theorem:
Δ rtq Δ rts
hypotenuse² - base² = height²
20² - (25 - x)² = 15² - x²
400 - (625 + x² - 50x) = 225 - x²
400 - 625 - x² + 50x = 225 - x²
-225 - x² + 50x - 225 + x² = 0
-450 + 50 x = 0
50x = 450
x = 450/50
x = 9
Base of Δ rtq = tq = 25 - x
tq = 25 - 9
tq = 16
The provided function is:
P = 0.04x + 0.05y + 0.06(16-x-y)
To determine the function's value at each vertex, simply plug in the respective x and y coordinates into the equation to find the value of P as shown below:
1- For (8,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(8) + 0.05(1) + 0.06(16-8-1)
P = 0.79
2- For (14,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(14) + 0.05(1) + 0.06(16-14-1)
P = 0.67
3- For (3,6):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(3) + 0.05(6) + 0.06(16-3-6)
P = 0.84
4- For (5,10):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(5) + 0.05(10) + 0.06(16-5-10)
P = 0.76
I hope this is useful:)
