Explanation:
Initial moles of ethanoic acid = 0.020 mol
At equilibrium, half of the ethanoic acid molecules have reacted.
Thus, moles of ethanoic acid reacted = 0.020 mol * (50% / 100%)
= 0.010 mol
Moles of ethanoic acid remaining = 0.020 mol - 0.010 mol = 0.010 mol
The moles of product 
gas formed are determined as follows:
0.010 mol CH3COOH * (1 mol / 2 mol CH3COOH)
= 0.005 mol
Consequently, the total moles of gas present in the vessel at equilibrium are 0.010 mol CH3COOH and 0.005 mol
Total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol
Next, let’s determine the pressure:
0.020 mol of gas has a pressure of 0.74 atm; so under the same conditions, we find the pressure exerted by 0.015 mol of gas:
P1/n1 = P2/n2
P2 = P1*(n2 / n1)
= 0.74 atm * (0.015 mol / 0.020 mol)
= 0.555 atm
The experimental setup involves assessing the temperature of the pizza, which serves as the dependent variable, after being allowed to cool in various thermal environments over a consistent time period used as a control. The following parameters are considered: The initial temperature of the pizza is 400°F, the freezer temperature is 0°F, the refrigerator is at 40°F, and the countertop is 78°F. The independent variable is the heat level experienced by the hot pizza, while the dependent one indicates the temperature it achieves during the cooling process. The plan for the experiment entails: 1) Positioning the pizza at 400°F in each heat setting (freezer, refrigerator, countertop) for the same duration, subsequently documenting the final temperature of the pizza. 2) The option yielding the lowest temperature after that timeframe indicates the fastest cooling method for the pizza.
Response:
The alteration in color.
Explanation:
The apple browns due to the oxidation process. This occurs when oxygen and water molecules from the air interact with it, resulting in oxidation. The oxidation process is notably rapid at room temperature.
For instance, if the peeled apple is placed in the refrigerator, it takes longer to oxidize and turn brown, but if left at room temperature, it quickly turns brown.
When oxygen interacts with the peeled apple, it activates the polyphenol oxidase enzyme, oxidizing the phenolic compounds and forming quinones, which then react with amino acids to create the brown coloration.
The enthalpy change in this scenario totals 7.205 KJ. The task is to compute the enthalpy variation during the conversion of 10.0 g of ice at -25.0°C into water at 80.0°C, factoring in specific heats and enthalpy for phase transitions.
