A sealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. The total pressure of t

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

Based on Archimedes' principle, the mass of fresh water and the mass of the cup are equal to the mass of the same volume of seawater.

The mass of freshwater can be calculated using density times volume.

1 cm³ is equivalent to 1 mL.

The mass of freshwater is 0.999 g/cm³ multiplied by 735 cm³, which results in 734.265 g.

The total mass of the freshwater and cup combined is 734.265 g plus 25 g, equating to 759.265 g.

This means the mass for an equal volume of seawater is 759.265 g.

The volume of the seawater displaced is 735 mL, which is 0.735 L (assuming the cup's volume can be disregarded).

We know that 1 liter equals 1000 cm³ or 1000 mL.

The density of seawater can be determined as mass divided by volume.

The density of seawater becomes 759.265 g divided by 0.735 L, yielding 1033.01 g/L.

Conversely, the density of freshwater in g/L is calculated as 0.999 g/(1/1000) L, equating to 999 g/L.

The mass of salt dissolved in 1 liter of seawater is calculated as 1033.01 g - 999 g, which equals 34.01 g.

Thus, the amount of salt in 1 L of seawater is 34 g.

Answer:

The concentration of P in the pond at equilibrium is 0.034 g/m³

Explanation:

Given the total mass = 49.9 g

1 day = 24 hours

mass per hour;

Incoming mass = (49.9 g / day) * (1 day /24 hr )

            = 2.079 g/hr

Outgoing mass = 0

Given the half-life = 3.4 hours

For a first-order reaction; k, the rate constant = ln2/t, where t is the half-time

                     ln 2= 0.693, V= volume

                     k = 0.693 / t_half = 0.693 / 3.4 = 0.2038 hr⁻¹

Mass lost to sunlight = k V  

= Incoming mass per hour / kV

= 2.079 g/hr / (0.2038 hr⁻¹ x 300 m³)

0.034 g/m³

Answer:Sugar-water is a mixture

Explanation:

If it consists of pure sugar, it's classified as neither; however, when mixed with water, it forms a homogeneous mixture.

Response:

3:1

Explanation:

Stearic acid - C18H36O2

Fructose- C6H12O6

The energy content in food is largely proportional to the carbon content. This can be expressed as:

C18/C6 = 3 or 3:1

This illustrates why fats and oils serve as the primary energy source for the body rather than carbohydrates. This is because fats and oils contain significantly higher amounts of carbon compared to carbohydrates.