Answer:
The continuation of the question is
Which explains the reasoning behind this fact?
Their DNA comprises different codon sequences.
It is composed of four distinct bases.
Kai received more proteins from one parent compared to the other.
The varied inheritance of amino acids from her parents led to the difference.
The correct response is Their DNA comprises different codon sequences.
DNA, or Deoxyribonucleic acid, consists of nitrogenous base pairs, a phosphate group, and deoxyribose sugar. The amino acids formed from these bases result in varied expression of traits. This variation stems from the diversity in coding sequences since there are over 60 distinct codon combinations. This accounts for the slight differences between Kai and her parents.
The proper response is "yes, yes, no" or "B, B, A".
Clarification:
In this hypothetical situation, an inhibitor obstructs the function of motor proteins in the kinetochore while still allowing the kinetochore to stay attached to the spindle. The animal cells treated with this inhibitor can elongate during mitosis, leading to the separation of sister chromatids, but the chromosomes will remain still instead of moving to the poles of the cell. The only action the inhibitor affects is the motor protein function, which is responsible for the movement of chromosomes to the poles during cell mitosis.
c. bivalents. In the initial phase of meiosis, specifically during prophase, bivalents are created, which consist of a tetrad made up of two paired chromosomes and four chromatids—each chromosome originating from one parent. In contrast, mitosis does not involve the formation of bivalents, although chromatids, homologs, centromeres, and spindles are present in both processes.
DNA replication is conducted by the polymerase II enzyme within eukaryotic cells. This enzyme incorporates nucleotides that are complementary to the leading strand and then to an RNA strand that starts the replication process.
When the 3' _ >5' exonuclease detects a mismatched pair of bases, it cuts and removes those bases. The polymerase II then fits the correct base pair and continues the replication process.
