answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kozerog
1 month ago
6

Evaluate 8a-1+0.5b8a−1+0.5b8, a, minus, 1, plus, 0, point, 5, b when a=\dfrac14a=

Mathematics
2 answers:
Zina [12.3K]1 month ago
7 0

Response: 6

Detailed explanation:

Consider the expression given below:

8a-1+0.5b

You must insert the values of "a" and "b" into the expression. The values you need are:

a=\frac{1}{4}\\\\b=10

Next;

8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)

Now proceed to carry out the multiplications:

=\frac{8}{4}-1+5=2-1+5

The concluding step is to sum the results. Thus, the final answer obtained is:

=6

Zina [12.3K]1 month ago
5 0

Result: 6

Detailed breakdown:

You might be interested in
Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu
zzz [12365]

Response:

Detailed explanation:

Greetings!

You have the variable

X: Area eligible for painting with a can of spray paint (feet²)

This variable is normally distributed with a mean of μ= 25 feet² and a standard deviation of δ= 3 feet²

As this variable has a normal distribution, it needs to be converted into the standard normal form to utilize tabulated cumulative probabilities.

a.

P(X>27)

The first step involves standardizing the X value using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Having determined the Z value, you can find it in the table, but since the table includes probabilities for P(Z, the following conversion must be applied:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

b.

A sample of 20 cans was taken, and you need to ascertain the probability of averaging a coverage area of 540 feet².

The sample mean maintains the same distribution as its source variable, but its variance is influenced by sample size, thus it is normally distributed with parameters:

X[bar]~N(μ;δ²/n)

To cover 540 feet² with 20 cans, the average coverage must be approximately 540/20= 27 feet² per can.

c.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

d.

No, if the distribution is not normal and skewed, the normal distribution should not be applied for calculating probabilities. While the central limit theorem might approximate the sampling distribution to normal when the sample size is 30 or larger, that isn’t applicable here.

I trust this information is helpful!

4 0
2 months ago
Thursday is ladies night at the slurp and burp bar and grill. all adult beverages are $ 1.25 for women and $ 2.50 for men. a tot
babunello [11817]
The ratio of women to men is 34 to 382. To find the total sales, we compute 382 multiplied by 2.50, resulting in $955. For women, the calculation is 34 multiplied by 1.25, which equals $42.50. Therefore, summing these amounts gives us $955 + $42.50 = $997.50.
7 0
1 month ago
Read 2 more answers
Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr
Svet_ta [12734]
Total Cost, C = $(16S + 56). Step-by-step explanation: Chris purchases 8 more Ninja Turtles than Star Wars action figures. The cost per Ninja Turtle is $7, while each Star Wars figure costs $9. If we let S represent the number of Star Wars figures bought, then the number of Ninja Turtles becomes S + 8. The cost for S Star Wars figures is $9S. Similarly, for (S + 8) Ninja Turtles, the total cost is $(7S + 56). Therefore, the overall Total Cost is represented by the sum of the costs for both types of figures, leading to the Total Cost being expressed as C = 9S + (7S + 56).
4 0
1 month ago
A space probe is controlled by 7 different instructions from the ground. the probabilities of sending these instructions vary -
Zina [12379]
The space probe must be able to recognize 7 distinct command types.
The number of combinations that can be encoded using n bits is 2^n. Thus, the minimum number of bits required to encode at least 7 different commands would be:

2^n > 7
2^n > 2^2.80
n > 2.80
n=3

A minimum of 3 bits is required
4 0
2 months ago
Read 2 more answers
Other questions:
  • Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for
    15·2 answers
  • If 4A = 3B = 2C, find A : B : C
    15·2 answers
  • A skydiver is 760 meters above the ground when he opens his parachute. After opening the parachute, he descends at a constant sp
    6·2 answers
  • Marcus and Jeremy both evaluated the expression −52 + 3. Marcus said the answer was −22. Jeremy said the answer was 28. Who is c
    9·1 answer
  • The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown.
    10·2 answers
  • Please Answer , question in the screenshot
    12·1 answer
  • what is the sum of a 7-term geometric series if the first term is −6, the last term is −24,576, and the common ratio is −4? −32,
    8·1 answer
  • Cam wants to find 509-106. Which steps can he use to find the difference
    14·1 answer
  • Alberto conducted an experiment by rolling a fair six-sided number cube 60 times. He rolled a 2 fifteen times. Which statement a
    12·2 answers
  • 1.<br> Simplify: 2.6 x 8.4-5.4<br> A. 2.32<br> B. 7.8<br> C. 16.44<br> D. 21.3
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!