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Karo-lina-s
1 month ago
15

the solution is n = –2 verified as a solution to the equation 1.4n 2 = 2n 3.2. what is the last line of the justification? a.0.8

= 0.8 b.–0.8 = –0.8 c.3 = 3 d.–3 = –3
Mathematics
1 answer:
Inessa [12.5K]1 month ago
5 0
The proof:
1.4 · ( -2 ) + 2 = 2 · ( -2 ) + 3.2
-2.8 + 2 = - 4 + 3.2
- 0.8 = - 0.8
Answer: B)
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Answer:

The likelihood that the rock contains raritanium is 0.9670

Step-by-step explanation:

Define the following events

Z: the sample contains raritanium

Y: the detector's reading is positive

Z': the sample does not have raritanium

Y': the detector's reading is negative

P(z) = 0.13

P(y'/z) = 0.02

P(y/z')= 0.005

We aim to determine p(z/y)

= p(z/y) = p(z ∩ y)/p(y)

= P(z) - p(z∩y)/0.13 = 0.02

Keep in mind p(z) = 0.13

Applying cross multiplication gives us

0.13 - p(z ∩ y) = 0.02 x 0.13

0.13 - p(z ∩ y) = 0.0026

-p(z ∩ y) = 0.0026 - 0.13

Therefore,

p(z ∩ y) = 0.1274

P(y/z')= 0.005

P(z∩y') = 0.005

Since p(z) = 0.13

P(z') = 1-0.13

P(y) - p(z∩y)/0.87 = 0.005

Cross multiplying gives

P(y) - 0.1274 = 0.005x0.87

P(y) = 0.1274+0.00435

P(y) = 0.13175

We assess 0.1274/0.13175

= 0.9670

Hence, we conclude that the probability of the rock containing raritanium is 0.9670

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