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gtnhenbr
2 days ago
14

Eric wants to buy a video game that cost $24 but he only wants to spend 40% of your savings. How much must Eric saying in order

to buy the game
Mathematics
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A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract
AnnZ [12381]

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Detailed solution:

Question 1)

We are provided with two linear equations representing lines, and we need to find the intersection point that solves the system.

The lines given are:

Line 1 equation:

y=\frac{-7}{4}x+\frac{5}{2}

This line passes through points (0, 2.5) and (2.2, -1.4).

Line 2 equation:

y=\frac{3}{4}x-3

The second line goes through (0, -3) and (2.2, -1.4).

According to the graph and data, the solution to the system is the coordinate where both lines intersect.

The solution to a system of linear equations is the coordinate pair common to both lines, i.e., the intersection point.

Here, both lines share the point (2.2, -1.4), indicating it is their intersection and the solution.

Therefore, the solution for question 1 is (2.2, -1.4).

Question 2)

The equations given are:

y = 1.5x - 1               Equation 1

y = 1                           Equation 2

The method of substitution can be used to find the solution.

Replacing y from Equation 2 into Equation 1 gives:

1 = 1.5x - 1

Add 1 to both sides:

2 = 1.5x

Dividing both sides by 1.5 yields:

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the system is (1.33, 1).

5 0
3 months ago
Read 2 more answers
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
lawyer [12517]
The response indicates that the test comprises 10 questions worth 3 points each and 14 questions worth 5 points. If there are any queries, feel free to ask!!! Thank you!
8 0
2 months ago
Read 2 more answers
A photographer sells large photos for $27 profit and small photos for an $11 profit.This past year,she sold 126 photos and made
Leona [12618]

Answer:

The photographer sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can create a system of equations based on the details provided. Let X represent small photos and Z represent large photos.

It is given that the total number of photos sold is 126:

X + Z = 126

Additionally, she generated $2,250 from selling specific amounts of small and large photos, stated as:

$2,250 = $11X + $27Z

From the first equation, we know X=126-Z. Substituting this into the second equation gives:

2,250 = 11(126-Z) + 27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54, which indicates the number of large photos sold. To find X:

X = 126 - Z

X = 126 - 54

X = 72, representing the small photos sold.

3 0
3 months ago
A music buff wants to estimate the percentage of students at a midwestern university who believe that elvis is still alive. how
Leona [12618]
Lacking information on the proportion, we will assume the sample proportion is 0.50

thus,
p = 0.50
The margin of error is set at 10 percentage points. This indicates that the error on either side of the population proportion is 5%, so E = 0.05
z = 1.645 (Z value for a confidence level of 90%)

The calculation for the margin of error when estimating population proportions follows:

E=z* \sqrt{ \frac{p(1-p)}{n} } \\ \\ 
 \frac{E}{z} = \sqrt{ \frac{p(1-p)}{n} } \\ \\ 
( \frac{E}{z} )^{2}= \frac{p(1-p)}{n} \\ \\ 
n= p(1-p)* (\frac{z}{E})^{2} \\ \\ 
n=271

Consequently, 271 students need to be part of the sample.
5 0
2 months ago
Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche
tester [12383]

Response:

The height of the water when it reaches 4 inches is \frac{3}{8\times \pi} inch/s.

Detailed Explanation:

Flow rate of water from the cone = R=\frac{3}{2} inch^3/s

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}

r = h/2

Volume of the cone = V=\frac{1}{3}\pi r^2h

V=\frac{1}{3}\pi r^2h

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}

\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}

\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

h = 4 inches

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2

\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s

The height of the water when it is 4 inches deep is \frac{3}{8\times \pi} inch/s.

6 0
3 months ago
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