Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

Question

Shkiper50

8 days ago

6

Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

at point 1. draw ann's path. represent ann's walk with a vector of length 80 meters.

Mathematics

2 answers:

PIT_PIT [3.9K] · Answer 1 · 2026-02-25T17:38:01+03:00

Response:

Anna's walk represented as a vector is shown in $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ , please refer to the attachment.

Explanation:

Assuming the origin is point 1, where Anna begins her walk.

She walks 80 meters in a straight line at an angle of 33° north of east from point 1, as illustrated below.

Breaking this down into vector components, the vertical component amounts to 80Sin33°, and the horizontal component to 80Cos33°, as depicted in figure (2).

Anna's walk represented as a vector is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Therefore, Anna's walk can be illustrated as a vector depicted in $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ .

Zina [3.9K] · Answer 2 · 2026-02-25T17:37:06+03:00

Ann walks 80 meters at a heading of 33° north of east. This can be expressed as a vector with
r = 80 m and
θ = 33°
To graph this, create a coordinate system consisting of two intersecting lines at right angles to each other, marked with the origin. Next, draw a ray that corresponds with the angle of 33° north of east. From the origin, along that ray, measure 80 m or use a scale for accurate representation.