Answer:
The total price for one loaf of bread combined with one package of cheese is $6.5.
Step-by-step explanation:
Given:
Mason purchased 6 loaves of bread and 3 cheese packages for a total of $27.
The price of one cheese package exceeds the price of one loaf of bread by $1.50.
To find: The sum cost of a single loaf of bread plus one cheese package.
Solution:
Let the price per loaf of bread be $x.
The cost for 6 loaves is $6x.
Let the price per cheese package be $y.
The cost for 3 cheese packages is $3y.
We know the total for both is $27:
6x + 3y = 27 ----(A)
Also, the cheese package costs $1.50 more than a loaf of bread:
y = x + 1.50 ----(B)
Using substitution, plug (B) into (A):
6x + 3(x + 1.50) = 27
6x + 3x + 4.5 = 27
9x + 4.5 = 27
9x = 22.5
x = 2.5
Therefore, the price of one loaf of bread is $2.5.
Now substitute $2.5 for x in (B):
y = 2.5 + 1.50 = 4
So, one cheese package costs $4.
Hence, the combined price is $2.5 + $4 = $6.5
Therefore, the combined cost of one loaf of bread and one package of cheese equals $6.5.