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dsp73
7 days ago
13

Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6 with a different number appear

ing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6?
Mathematics
1 answer:
babunello [3.6K]7 days ago
8 0

Answer:

0.2 = 20%

Step-by-step explanation:

The combinations that yield a total of 6 or lower include:

(1,1), (1,2), (1,3), (1,4), (1,5),

(2,1), (2,2), (2,3), (2,4),

(3,1), (3,2), (3,3),

(4,1), (4,2),

(5,1)

(15 combinations in total)

The combinations resulting in a total of 4 are:

(1,3), (2,2), (3,1)

(3 combinations in total)

Thus, the probability of obtaining a sum of 4, given that the total is 6 or less is:

P = 3/15 = 0.2 = 20%

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Answer:

The amount of ovens that must be produced in a week to earn a $1610 profit is 70.

Step-by-step explanation:

Given:

A small-appliance manufacturer determines the profit P (in dollars) from producing x microwave ovens weekly by the formula:

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So, set P = 1610, then solve for x:

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Multiply both sides by 10:

1610\cdot \:10=\frac{1}{10}x\left(300-x\right)\cdot \:10

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16100=300x-x^2

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Solving for x gives:

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Hence, the valid solution is x=70.

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Answer:

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Step-by-step explanation:

Given the inequality is -3(2x - 5) < 5(2 - x)

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A circle is open at 5 with a bold line extending right from 5 ⇒ 4th option (see diagram)

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