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dsp73
3 months ago
13

Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6 with a different number appear

ing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6?
Mathematics
1 answer:
babunello [11.8K]3 months ago
8 0

Answer:

0.2 = 20%

Step-by-step explanation:

The combinations that yield a total of 6 or lower include:

(1,1), (1,2), (1,3), (1,4), (1,5),

(2,1), (2,2), (2,3), (2,4),

(3,1), (3,2), (3,3),

(4,1), (4,2),

(5,1)

(15 combinations in total)

The combinations resulting in a total of 4 are:

(1,3), (2,2), (3,1)

(3 combinations in total)

Thus, the probability of obtaining a sum of 4, given that the total is 6 or less is:

P = 3/15 = 0.2 = 20%

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Suma numerelor de forma a4b cu produsul cifrelor 24 este egala cu
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