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3 months ago

9

mother had 1 1/2 dozen of eggs in refrigerator. she used 1/3 of eggs. what part of the eggs was used?

2 answers:

Leona [12.6K]3 months ago

5 0

Answer: 1/2

Step-by-step explanation:

1 1/2 is equivalent to 3/2.

Multiplying 1/3 by 3/2 results in 1/2.

Svet_ta [12.7K]3 months ago

5 0

1/2.....because I asked my mother, and she’s quite good at math.

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A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from

babunello [11817]

Revenue = price * quantity of backpacks
quantity of backpacks = -2p + 50

For p = 9: -2(9) + 50 = -18 + 50 = 32
thus, revenue = 9 * 32 = 288

For p = 12: -2(12) + 50 = -24 + 50 = 26
therefore, revenue = 12 * 26 = 312

For p = 12.50: -2(12.50) + 50 = -25 + 50 = 25
thus, revenue = 12.50 * 25 = 312.50 MAXIMIZES REVENUE

For p = 15: -2(15) + 50 = -30 + 50 = 20
so, revenue = 15 * 20 = 300

8 0

3 months ago

Read 2 more answers

Arrange the entries of matrix A in increasing order of their cofactors values

Zina [12379]

To ascertain the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

First, eliminate the relevant row and column linked to the specified entries and calculate the determinant of the leftover $2\times 2$ matrix while applying alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore, the entries arranged in increasing order of their cofactors values are;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

2 months ago

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A car with an initial cost of $23,000 is decreasing in value at a rate of 8% each year. Write the exponential decay function des

tester [12383]

Answer:

Step-by-step explanation:

We will utilize the exponential decay formula described as

A = P(1 - r/n)^(nt)

Where

A symbolizes the value after a time period t.

n refers to the timeframe for value loss calculation

t indicates the number of years.

P stands for the population value.

r indicates the rate of decrease.

Based on the provided data,

P = 23000

r = 8% = 8/100 = 0.08

n = 1

Thus, the exponential decay function fitting this situation is

A = 23000(1 - 0.08/n)^1)^ t

A = 23000(0.92)^t

If A = 15000, it follows that

15000 = 23000(0.92)^t

0.92^t = 15000/23000 = 0.6522

Taking logarithm of both sides to base 10

Log(0.92^t) = log(0.6522)

t log(0.92) = log(0.6522)

- 0.036t = - 0.1856

t = - 0.1856/- 0.036

We find t = 5 years rounded to the nearest year

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2 months ago