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Simora
1 month ago
7

A sailor on a trans-Pacific solo voyage notices one day that if he puts 735.mL of fresh water into a plastic cup weighing 25.0g,

the cup floats in the seawater around his boat with the fresh water inside the cup at exactly the same level as the seawater outside the cup (see sketch at right).
Calculate the amount of salt dissolved in each liter of seawater. Be sure your answer has a unit symbol, if needed, and round it to 2 significant digits.

You'll need to know that the density of fresh water at the temperature of the sea around the sailor is 0.999/gcm3. You'll also want to remember Archimedes' Principle, that objects float when they displace a mass of water equal to their own mass.
Chemistry
1 answer:
Anarel [2.9K]1 month ago
4 0

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

Based on Archimedes' principle, the mass of fresh water and the mass of the cup are equal to the mass of the same volume of seawater.

The mass of freshwater can be calculated using density times volume.

1 cm³ is equivalent to 1 mL.

The mass of freshwater is 0.999 g/cm³ multiplied by 735 cm³, which results in 734.265 g.

The total mass of the freshwater and cup combined is 734.265 g plus 25 g, equating to 759.265 g.

This means the mass for an equal volume of seawater is 759.265 g.

The volume of the seawater displaced is 735 mL, which is 0.735 L (assuming the cup's volume can be disregarded).

We know that 1 liter equals 1000 cm³ or 1000 mL.

The density of seawater can be determined as mass divided by volume.

The density of seawater becomes 759.265 g divided by 0.735 L, yielding 1033.01 g/L.

Conversely, the density of freshwater in g/L is calculated as 0.999 g/(1/1000) L, equating to 999 g/L.

The mass of salt dissolved in 1 liter of seawater is calculated as 1033.01 g - 999 g, which equals 34.01 g.

Thus, the amount of salt in 1 L of seawater is 34 g.

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At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
castortr0y [3046]
To find the temperature at which the volume of the gas would be 0.550 L, given that it is 0.432 L at -20.0 °C, apply Charles’s Law.

The formula is v1/T1 = v2/T2
Known values:
V1 = 0.550 L
T1 = ?
T2 = -20°C + 273 = 253 K
V2 = 0.432 L

Rearranging for T1:
T1 = (V1 × T2) / V2

Calculating:
T1 = (0.55 L × 253) / 0.432 L = 322.11 K or 49.11°C
8 0
2 months ago
Read 2 more answers
for the final step of the copper cycle, zinc, Zn(s), is added to copper sulfate, CuSO4(aq). Elemental copper appears as a solid.
Alekssandra [3086]

Elemental zinc replaces copper

Explanation:

During this reaction, the zinc added to the copper sulfate solution has replaced the copper present in the compound.

This process is known as a single displacement reaction.

                      Zn + CuSO₄     →   ZnSO₄    +  Cu

This represents the reaction in the recycling process.

The reaction is influenced by the elements' positions within the reactivity series of metals.

  • In a single displacement reaction, an element higher in the reactivity series displaces one that is lower.
  • Zinc ranks above copper in this series, allowing it to react with sulfate.
  • Consequently, copper is pushed out as a solid product in the solution.
  • Elements positioned higher in this series exhibit greater reactivity

learn more:

Chemical reaction

5 0
14 days ago
How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of
eduard [2782]

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

  • The solution's volume is 350 mL
  • The solution's molarity is 2.75 M
  • The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

4 0
1 month ago
Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation
alisha [2963]

I believe this question has five choices available:

 

>an SN2 process has happened with reversal of configuration

>racemization followed by an S N 2 reaction

>an SN1 process has occurred resulting in reversal of configuration

>an SN1 reaction has taken place due to the formation of a carbocation

>an SN1 event followed by an S N 2 “backside” attack

 

 

 

The correct choice is:

an SN1 reaction has occurred due to carbocation formation 

4 0
22 days ago
PART A: Use the following glycolytic reaction to answer the question. If the concentration of DHAP is 0.125 M and the concentrat
alisha [2963]

Answer:

For A: The change in free energy for the reaction is -5339.76 J/mol

For B: Free energy change is expressed in kJ/mol

For C: The forward reaction favors progression, while the reverse reaction does not.

Explanation:

Regarding the specified chemical reaction:

DHAP\rightleftharpoons G_3P

  • For A:

The relationship between standard Gibbs free energy and equilibrium constant is as follows:

\Delta G^o=-RT\ln K_{eq}

The free energy change can be calculated using the following equation:

\Delta G=\Delta G^o+RT\ln Q

Or,

\Delta G=-RT^o\ln K_{eq}+RT\ln Q

where,

\Delta G = Change in free energy

R = Gas constant = 8.314J/K mol

T^o = standard temperature = 25^oC=[273+25]K=298K

T = temperature of the cell = 37^oC=[273+37]K=310K

K_[eq} = equilibrium constant = 5.4\times 10^{-2}

Q = reaction quotient = \frac{[G_3P]}{[DHAP]}

[G_3P] = 0.06 M

[DHAP] = 0.125 M

Substituting the values into the equation yields:

\Delta G=[-(8.314J/mol.K\times 298K\times \ln (5.4\times 10^{-2}))]+[(8.314J/mol.K\times 310K\times \ln (\frac{0.06}{0.125}))]\\\\\Delta G=-[-7231.46]+[-1891.7]=-5339.76J/mol

Thus, the change in free energy for the reaction is -5339.76 J/mol

  • For B:

To convert the free energy change to kilojoules, we apply the conversion factor:

1 kJ = 1000 J

So, -5339.76J/mol\times \frac{1kJ}{1000J}=-5.34kJ/mol

Consequently, the free energy change's units are kJ/mol

  • For C:

For spontaneity in the reaction, the Gibbs free energy must be negative. However, the calculations indicate a positive Gibbs free energy, leading to the conclusion that the reaction is not spontaneous.

The free energy change of the reaction is negative.

Consequently, the forward reaction is favored and the reverse reaction is not favored.

8 0
1 month ago
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