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iris
2 months ago
7

An element is a main constituent of paper, diamond and clothes etc. It forms covalent bonds with itself and other elements:- (1)

identify the element (2) write the electron dot structure of its oxide. (3) draw the electron dot structure of methane and ethene.

Chemistry
2 answers:
alisha [2.9K]2 months ago
7 0

Explanation:

1) The primary element in paper, diamond, and clothing is carbon. Carbon possesses the unique ability to form robust covalent bonds with other carbon atoms, resulting in intricate organic structures.

2) Carbon forms two oxides: carbon dioxide CO_2 and carbon monoxide CO.

Structures are displayed in an image.

3) A methane molecule contains one carbon atom.

Methane = CH_4

In ethene, two carbon atoms are connected by a double bond.

Ethene = C_2H_4

The electron dot structures for methane and ethene are illustrated in an image

lorasvet [2.7K]2 months ago
6 0

Answer 1) Carbon - This element is a key component of paper in the form of cellulose, diamond consists entirely of carbon, and most fabric fibers are carbon-based. It has four valence electrons in its outer shell, enabling it to form covalent bonds with other elements or with itself by donating or accepting electrons to achieve a stable octet.


Answer 2) There are two types of carbon oxides:

i) CO and ii) CO_{2}


Images for the electron dot structures are provided.


Answer 3) The structure of methane and ethene can be found in the accompanying image.

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3 months ago
A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
Tems11 [2777]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is C_4H_4O

The empirical weight is calculated as C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula can be derived as=2\times C_4H_4O=C_8H_8O_2

4 0
2 months ago
How many atoms of Mg are present in 97.22 grams of Mg?
VMariaS [2998]

Answer: The correct choice is (b).

Explanation:

We have the mass of Magnesium at 97.22 g, and the molar mass of Magnesium is 24.305 g/mol.

Therefore, the calculation for the number of moles is as follows.

          Number of moles = \frac{mass given in grams}{Molar mass}

                                 = \frac{97.22 g}{24.305 g/mol}  

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Additionally, it is known that one mole contains 6.023 \times 10^{23} atoms/mol. Thus, we calculate the total number of atoms in 4 moles as follows.

               4 mol \times 6.023 \times 10^{23} atoms/mol

               = 24.08 \times 10^{23} atoms

or,            = 2.408 \times 10^{23} atoms

Hence, we conclude that in 97.22 grams of Magnesium, there are 2.408 \times 10^{23} atoms.

7 0
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