Determine the freezing point of a solution which contains 0.31 mol of sucrose in 175 g of water. kf = 1.86ï°c/m

Answer: The percentage abundance for isotope is 3.09 %.

Explanation:

The average atomic mass of an element is calculated by taking the sum of the masses of all isotopes weighted by their respective natural fractional abundances.

To compute average atomic mass, the following formula is applied:

  .....(1)

From the information provided:

Let the fractional abundance for isotope be 'x'

• For isotope:

Mass of isotope = 27.9769 amu

Percentage abundance of isotope = 92.22 %

Fractional abundance for isotope = 0.9222

• For isotope:

Mass of isotope = 28.9764 amu

Percentage abundance for isotope = 4.68%

Fractional abundance of isotope = 0.0468

• For isotope:

Mass of isotope = 29.9737 amu

Fractional abundance for isotope = x

• The average atomic mass of silicon is 28.084 amu

By inserting these values into equation 1, we derive:

To convert this fractional abundance into a percentage, multiply by 100:

This shows that the percentage abundance for isotope is 3.09 %.

The molar mass of C2F4 (tetrafluoroethylene) is 100 g/mol. To find the number of moles of C2F4 in the specified quantity,
n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The calculation for the number of molecules per mole is done via the equation,
(0.0585 mols) x (6.022 x 10^23)
Given that each molecule contains 4 F atoms, then,
(0.0585 mols) x (6.022 x 10^23)(4)
= 1.41 x 10^23 atoms of F

Answer:

The reaction will proceed in the forward direction, resulting in the reduction of NiO to Ni

Explanation:

Step 1: Provided data

Kp = 6.0 * 10²

Pressure of CO = 150 torr

Total pressure remains under 760 torr

Step 2: The balanced reaction equation:

NiO(s) + CO(g) ⇆ Ni(s) + CO2(g)

Step 3: Determine P(CO) and P(CO2)

For this equilibrium, the Kp expression is:

Kp = P(CO2)/P(CO) = 6.0*10^2

Given that NiO and Ni are solids, they do not affect the Kp

⇒ with P(CO) = 150 torr

⇒ P(CO) = 760 - 150 = 610 torr

Step 4: Calculate the reaction quotient

Q = 610/150 = 4.1

Since Q is significantly less than Kp, there are more reactants than products. Some reactants will convert into products, driving the reaction rightward.

Thus, the reaction will proceed forward, leading to the reduction of NiO to Ni.

<span>4.3065 g To begin with, consult the atomic masses for each involved element. Atomic weight of Calcium = 40.078 Atomic weight of Carbon = 12.0107 Atomic weight of Hydrogen = 1.00794 Atomic weight of Oxygen = 15.999 Atomic weight of Sulfur = 32.065 Next, compute the molar masses of both reactants and the product. Molar mass H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass CaCO3 = 40.078 + 12.0107 + 3 * 15.999 = 100.0857 g/mol Molar mass CaSO4 = 40.078 + 32.065 + 4 * 15.999 = 136.139 g/mol The balanced equation for the reaction between H2SO4 and CaCO3 is: CaCO3 + H2SO4 ==> CaSO4 + H2O + CO2 Thus, 1 mole each of CaCO3 and H2SO4 is necessary to generate 1 mole of CaSO4. Let's check the amount of moles we have for CaCO3 and H2SO4. CaCO3: 3.1660 g / 100.0857 g/mol = 0.031632891 mol H2SO4: 3.2900 g / 98.07688 g/mol = 0.033545113 mol H2SO4 is in slight excess, therefore CaCO3 is the limiting reactant, suggesting we can expect 0.031632891 moles of product. To find the mass, multiply the number of moles by the molar mass calculated previously. 0.031632891 mol * 136.139 g/mol = 4.306470148 g Given that we have 5 significant figures from our data, we round the final result to 5 figures, yielding 4.3065 g</span>

Answer: Pentane C5H12

Explanation:

The boiling point is defined as the temperature at which a liquid's vapor pressure matches the external pressure, causing the liquid to turn into vapor.

This compound is likely Pentane, represented as C5H12, since its boiling point falls between that of Butane, with the formula C4H10, and Hexane, with the formula C6H14.