The yearly income for an individual with an associate’s degree in 2001 was $53,166 and in 2003 it was $56,970. What is the ratio

Question

6 days ago

5

of the income in 2001 to the income in 2003 in simplest form?

2 answers:

lawyer [9.2K] · Answer 1 · 2026-03-21T20:06:02+03:00

Response:

$\frac{8861}{9495}$

Detailed explanation:

Income of an individual in 2001 = $\$ 53,166$

Income of an individual in 2003 = $\$ 56,970$

In this case, we aim to determine the ratio of income from 2001 to that from 2003 in its simplest form.

That is, we need to express $\frac{\$53,166}{\$ 56,970}$ in simplest terms.

A fraction is considered to be in simplest form if $\frac{a}{b}$ $HCF(a,b)=1$

Thus, we first find $HCF(53166,56970)$ then divide both the numerator and denominator by the HCF.

Here,

$53166=2\times 3\times 8861$

$56970=2\times 3\times 3\times 3\times 5\times 211$

On dividing both numerator and denominator by 6, we get $HCF(53166,56970)=2\times 3=6$

Zina [9.1K] · Answer 2 · 2026-03-21T20:07:22+03:00

6 0

Response:

8861: 9495

Detailed explanation:

The income ratio for the years 2001 to 2003:

53,166: 56,970

To simplify, divide both sides by 6:

8,861: 9,495

This can't be simplified further, so that is the final result!

8861: 9495

I hope this helps! Have a great day:)