A Sunday newspaper lists the 10 used car prices for a foreign compact, with age x measured in years and selling price y measured

Which function has no horizontal asymptote? F (x) = StartFraction 2 x minus 1 Over 3 x squared EndFraction f (x) = StartFraction

tester [12383]

Response:

$f(x)=\frac{2x^2}{3x-1}$

Detailed explanation:

The function $f(x)=\frac{2x-1}{3x}$ features a horizontal asymptote which is $y=\frac{2}{3}$

The function $f(x)=\frac{x-1}{3x}$ presents a horizontal asymptote which is $y=\frac{1}{3}$

One function $f(x)=\frac{2x^2}{3x-1}$ lacks a horizontal asymptote because the degree of its numerator surpasses that of the denominator,

The function $f(x)=\frac{3x^2}{x^2-1}$ displays a horizontal asymptote which is $y=3$

3 0

3 months ago

Read 2 more answers

I need help in this qustion.each unit costs 14p.how much do 942 units costs?

lawyer [12517]

The total cost amounts to £131.88 or 13188 pence.

8 0

3 months ago

What is the 1000th root of the expression 5(^10^10)

lawyer [12517]

Solution:

feet

Detailed explanation:

3 0

3 months ago

Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample

lawyer [12517]

Answer:

$\mu_{\bar x} = \mu = E(X) =30KWh$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3$

Step-by-step explanation:

Previous concepts

Normal distribution, is defined as a symmetric "probability distribution centered around the mean, indicating that values near the mean are more common than those further away".

The Z-score measures a value's relation to the mean of a set of values, displayed in terms of how many standard deviations away it is from that mean.

According to the central limit theorem, "with a population having mean μ and standard deviation σ, if we draw sufficient random samples from this population with replacement, the means of those samples will resemble a normal distribution, regardless of the original population's shape, as long as the sample size is large enough".

Solution to the problem

In this scenario, we select a sample size of n = 100

The central limit theorem informs us that the distribution of the sample mean $\bar X$ is defined by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Thus, the mean for the sample would be:

$\mu_{\bar x} = \mu = E(X) =30KWh$

And the standard deviation would be:

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3$

6 0

3 months ago