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Zielflug
4 days ago
7

For many purposes we can treat methane (CH) as an ideal gas at temperatures above its boiling point of - 161. °C. Suppose the te

mperature of a sample of methane gas is raised from 100.0 °C to 119.0 °C, and at the same time the pressure is decreased by 15.0%. increase Does the volume of the sample increase, decrease, or stay the same? decrease x 6 ? stays the same If you said the volume increases or decreases, calculate the percentage change in the volume. Round your answer to the nearest percent. 1%
Chemistry
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A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.
VMariaS [2998]

Response:

2200 mg of antibiotic

Explanation:

The prescribed antibiotic dosage is 40 mg/kg of body weight.

For a patient weighing 55 kg, we calculate the dose of antibiotic as follows:

If we analyze 40/1000000, we can determine antibiotic allocation in kg per kg of weight

= 0.00004 kg of antibiotic for each kilogram

0.00004 multiplied by 55 (to find out the required amount for a 55 kg individual)

= 0.0022 kg

This 0.0022 figure converts to milligrams as follows

0.0022*10^6

= 2200 mg of antibiotic is indicated for a patient weighing 55 kg.

4 0
2 months ago
A substance has a density of 4.5 g/cm3. The substance is heated and its density recalculated. What is the newly recorded density
lions [2927]

Response:

Aluminum

Clarification:

6 0
2 months ago
The volume of the ideal gas in the container is 9 m3. What would the volume be if four more blocks were placed on top of the lid
castortr0y [3046]
Response:
             4.5 m³

Resolution:
              The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.

After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).

Hence, The data established is,

                  P₁  =  4 atm

                  V₁  =  9 m³

                  P₂  =  8 atm

                  V₂  =?

Using Boyle's Law,

                               P₁ V₁  =  P₂ V₂

Resolving for V₂,
                               V₂  =  P₁ V₁ / P₂

Substituting values yields:
                               V₂  =  (4 atm × 9 m³) ÷ 8 atm

                               V₂  =  4.5 m³
0 0
3 months ago
Dicarbon monoxide, C2O, is found in dust clouds in space. Analysis of it shows that the sequence of atoms in this molecule is C–
castortr0y [3046]

Greetings,


The number of lone pairs of electrons in a C2O molecule is...

4

Each Oxygen atom forms two bonds with Carbon.


I hope this was useful!

-Char

8 0
3 months ago
Read 2 more answers
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