Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively? ex

Given data:

CO concentration in air = 15 ppm

Volume of air inhaled per breath = 0.50 L

Breaths taken per minute = 20

CO density = 1.2 g/L

Objective:

milligrams of CO inhaled over 6 hours

Clarification:

A concentration of 15 ppm of CO means that there are 15 liters of CO per 10⁶ liters of air

. Consequently, the volume of CO inhaled through 0.50 L of air is

= 15 L CO * 0.50 L air/10⁶ L air = 7.5 *10⁻⁶ L CO/breath

Next, considering there are 20 breaths in a minute,

the total number of breaths in 360 minutes (or 6 hours) will be

= 360 min * 20 breaths/1 min = 7200 breaths

Thus, the total volume of CO inhaled in that time frame is

= 7200 breaths * 7.50*10⁻⁶L/1 breath = 0.054 L

Given that the density of CO is 1.2 g/L

the mass of CO inhaled equals Density*Volume

= 0.054 * 1.2 = 0.0648 g = 64.8 mg

Thus, the mass of CO inhaled over 6 hours is 64.8 mg

The isotopic mass of 47Z is calculated to be 46.96 amu. Isotopes of a single element differ in neutron count, and to ascertain the relative atomic mass, we consider each isotope's mass weighted by their natural abundance. This provided a computation to derive the mass of 47Z.

Answer: 3.28 mins

Explanation:

Here’s how it breaks down:

Conversions

74 mph = 33.08 m/s

6.5 km = 6500 m

(6500 m)/(33.08 m/s) = 196.5 seconds

196.5 seconds is equivalent to 3.28 minutes

The element you are looking for is Pb (Lead). Just check the last orbital on the periodic table to find it!

Clarification:

The pertinent information is outlined as follows.

m = 10.0 kg = 10,000 g (since 1 kg = 1000 g)

Starting temperature of block 1, = (100 + 273) K = 373 K

Starting temperature of block 2, = (0 + 273) K = 273 K

Therefore, the heat lost by block 1 equals the heat received by block 2

It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.

Additionally, the relationship between enthalpy and temperature change is as follows.

=

= 1243550 J

or, = 1243.5 kJ

Next, determine the entropy change for block 1 as follows.

=

=

= -554.12 J/K

Now, the entropy change for block 2 is as follows.

   

           =

           =

           = 647.49 J/K

Thus, the total entropy is the sum of the entropy changes of both blocks.

                   = -554.12 J/K + 647.49 J/K

           = 93.37 J/K

In conclusion, for this reaction, the outcome is 1243.5 kJ and is 93.37 J/K.