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worty
18 days ago
5

The volume of the ideal gas in the container is 9 m3. What would the volume be if four more blocks were placed on top of the lid

of the container with the temperature of the gas kept constant? (The lid itself has a mass equal to that of two blocks.) a heated container filled with gas
a. 81 m3
b. 18 m3
c. 4.5 m3
d. 3 m3
Chemistry
1 answer:
castortr0y [2.6K]18 days ago
0 0
Response:
             4.5 m³

Resolution:
              The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.

After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).

Hence, The data established is,

                  P₁  =  4 atm

                  V₁  =  9 m³

                  P₂  =  8 atm

                  V₂  =?

Using Boyle's Law,

                               P₁ V₁  =  P₂ V₂

Resolving for V₂,
                               V₂  =  P₁ V₁ / P₂

Substituting values yields:
                               V₂  =  (4 atm × 9 m³) ÷ 8 atm

                               V₂  =  4.5 m³
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A 24.1-g mixture of nitrogen and carbon dioxide is found to occupy a volume of 15.1 L when measured at 870.2 mmHg and 31.2oC. Wh
eduard [2409]

Answer:

The mole fraction of nitrogen is   0.52

Explanation:

Provided information:

Temperature =  31.2 °C

Pressure = 870.2 mmHg

Volume = 15.1 L

Mass of the mixture = 24.1 g

Mole fraction of nitrogen =?

Process:

Converting pressure:

870.2 / 760 = 1.12 atm

Converting temperature:

31.2 + 273 = 304.2 K

Total moles calculation:

PV = nRT

n = PV/RT

n =  1.12 atm × 15.1 L / 0.0821 L.atm. mol⁻¹.K⁻¹ × 304.2 K

n = 16.9 L.atm.  / 25 L.atm. mol⁻¹

n = 0.676 mol

Let x be the number of moles of nitrogen.

Thus, the moles of CO₂ = 0.676 - x

The mass of nitrogen = x mol × 28 g/mol, and for CO₂ the mass = 44 g/mol (0.676 - x)

We have 24.1  = 28x + (29.7 - 44x)

Rearranging gives: 24.1 - 29.7  =  28x  - 44x

-5.6 = -16 x

Therefore, x = 0.35

Mole fraction of nitrogen:

Mole fraction of nitrogen = moles of nitrogen / total moles

Mole fraction of nitrogen =   0.35  mol / 0.676 mol

Mole fraction of nitrogen =   0.52

3 0
23 days ago
Butane (c4h10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. given δh°f[c4h10(g)] = –124.7
KiRa [2612]

The Δ H value for butane (g) is -124.7 kJ/mol.

The Δ H value for CO2 (g) is -393.5 kJ/mol.

The Δ H value for H2O (g) is -241.8 kJ/mol.

The mass of butane is 8.30 grams.

Butane has a molar mass of 58 g/mol.

Considering the reaction,

C₄H₁₀ + 6.5 O₂ = 4CO₂ + 5H₂O

To determine the Δ H° of the reaction:

ΔH°rxn = ∑nH° f (products) - ∑nH° f (reactants)

By substituting values, we find that

Δ H° rxn = 4 (-393.5) + 5 (-241.8) - (-124.7)

= -1574 -1209 + 124.7

= -2783 - 124.7

= -2658.3 kJ/mol

Now, we will calculate how many moles of butane are in 8.30 grams.

Number of moles = mass/molar mass

= 8.30 / 58

= 0.143 moles

Therefore, the total energy released during the reaction is given by,

Q = number of moles × ΔH° rxn

= 0.143 × (2658.3)

= 380.14 kJ

Thus, the total heat released in the reaction is 380.14 kJ.

6 0
1 month ago
Which of the following statements reasonably explains why this reaction has a low activation energy? View Available Hint(s) The
eduard [2409]

Answer;

Considering the types of bonds being created and severed in the transition state, the stability of this temporary structure is comparatively high.

Explanation;

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  • All chemical reactions, including exothermic ones, require activation energy to initiate. The activation energy is the least amount of energy needed for the reactants to come together, overcome opposing forces, and begin breaking bonds.
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10 days ago
Which of the following air pollutants is correctly paired with one of its major effects?
alisha [2691]

Response:

The accurate choice is;

Sulfur oxides linked to acid precipitation

Details:

Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.

Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;

The sulfur gas undergoes initial oxidation

SO₂ + OH → HOSO₂

The subsequent step involves producing sulfur trioxide

HOSO₂ + O₂ → HO₂ + SO₃

Finally, sulfur trioxide reacts with water to yield sulfuric acid

SO₃ + H₂O → H₂SO₄ (aq).


3 0
15 days ago
The atomic radius of magnesium is 150 pm. The atomic radius of strontium is 200 pm. What is the atomic radius of calcium
castortr0y [2628]

Answer:

Calcium's atomic radius is roughly 175 pm.

Explanation:

We know that magnesium has an atomic radius of 150 pm.

The atomic radius of strontium measures 200 pm.

Since calcium's position is between magnesium and strontium in group 2 of the periodic table, its atomic radius should be roughly averaged between magnesium's and strontium's atomic radii because atomic radius is not constant.

Thus;

Calcium's atomic radius is approximately calculated as follows;

The average atomic radius is (200 + 150)/2 = 175 pm.

7 0
1 month ago
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