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Lelu
2 days ago
10

Based on daily measurements, Bob's weight has a mean of 200 pounds with a standard deviation of 16 pounds, while Mary's weight h

as a mean of 125 pounds with a standard deviation of 10 pounds. Who has the smaller dispersion based on the coefficient of variation?
(A) Bob
(B) Mary
(C) They are the same
(D) All of the above
Mathematics
1 answer:
babunello [3.6K]2 days ago
6 0

Answer:

(C) They have the same coefficient of variation

Step-by-step explanation:

The coefficient of variation (CV) is calculated using the formula:

CV = \frac{\sigma}{\mu}

Where \sigma represents standard deviation and \mu represents the mean.

Bob's average weight is 200 pounds with a standard deviation of 16 pounds

This indicates that \sigma = 16, \mu = 200.

Thus, his coefficient of variation is

CV = \frac{16}{200} = 0.08

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.

This implies \sigma = 10, \mu = 125

Therefore, her coefficient of variation is

CV = \frac{10}{125} = 0.08

Since both have the same coefficient of variation, the accurate response is.

(C) They have the same coefficient of variation

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