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malfutka
4 days ago
15

Which equation represents an exponential function with an intitial value of 500? f(x) = 100(5)^x, f(x) = 100(x)^5, f(x) = 500(2)

^x, f(x) = 500(x)^2
Mathematics
You might be interested in
The perimeter of a rectangle is 202. The length is 26 more than 4 times the width. Find the dimensions
Inessa [12570]

Answer:

P = 2*(26+4y) + 4y

Upon solving for y, we find:

202= 52 +8y +4y

202= 52 +12 y

By substitution, we have:

150 = 12y

Thus, we arrive at:

y = \frac{150}{12}= 12.5

And for x, we determine:

x = 26 +4*12.5 = 76

This gives us a length of 76 and a width of 12.5.

Step-by-step explanation:

We are dealing with a rectangle. The formula for the perimeter is:

P= 2x+2y

Here, x denotes the length and y the width. The following conditions can be established:

x = 26 +4y

Substituting these values yields:

P = 2*(26+4y) + 4y

When we solve for y, we find:

202= 52 +8y +4y

202= 52 +12 y

By substitution, we obtain:

150 = 12y

Thus, we conclude:

y = \frac{150}{12}= 12.5

The length is found to be 76, while the width measures 12.5.

6 0
3 months ago
A statistics professor at a large university hypothesizes that students who take statistics in the morning typically do better t
Svet_ta [12734]

Answer:

The resulting value is 2.381

Step-by-step explanation:

Using the information presented in the question, we will calculate the evidence supporting the professor's hypothesis

Given that:

x₁ = 74,

n₁ = 36

s₁ = 8

x₂ = 68

n₂ = 36

s₂ = 10

The hypotheses can be outlined as:

The critical value is t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀₁

thus,

t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀ = 2.381

This implies a range of -2.381 to 2.381

Thus, we can support the professor's assertion.

5 0
2 months ago
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