A + B → AB: ✔ combination
AB → A + B: ✔ breakdown
Hydrocarbon + O2 → CO2 + H2O: <span>✔ oxidation</span>
AB + CD → AD + CB: <span>✔ exchange</span>
FeCl₃ reacts frequently with phenolic compounds.
I hope this is useful!!
The calculation of moles of chromium (III) nitrate produced is done as follows. First, you write the reaction equation: 3 Pb(NO3)2 + 2 Cr = 2 Cr(NO3)3 + 3 Pb. Then, by using the mole ratio from Pb(NO3)2 to Cr(NO3)3, which is 3 to 2, you can find the moles of Cr(NO3)3. Thus, for 0.85 moles of lead (IV) nitrate, it equates to 0.85 x 2 / 3 = 0.57 moles.
