Answer:
The work done in this process will be considered Negative.
Explanation:
The energy transferred by the system to the environment is negative
Therefore, if work is done on the system, it is labeled as positive. Conversely, when work is done by the system, it is regarded as negative.
In this scenario, the argon gas is expanding, and the work is exerted by the system into the surroundings (container), making the sign Negative.
Thus, the result for the work pertaining to this process will carry a Negative sign.
Answer:
Explanation:
Diethyl malonate possesses greater acidity compared to monocarbonyl substances (pKa=13) because its alpha hydrogens are linked to two carbonyl groups. Consequently, the malonic ester can be readily changed into its enolate ion by reacting it with sodium ethoxide in ethanol. When the malonic ester undergoes alkylation, a hydrogen atom in the alpha position becomes acidic, permitting another round of alkylation to yield a dialkylated malonic ester.
In this scenario, when diethyl malonate interacts with urea in the presence of sodium ethoxide base, the second alkylation step occurs within the molecule, producing a cyclic compound known as barbituric acid.
The response is:
No, the equation is not balanced. Neither the Nitrogen (N) nor the Hydrogen (H) are in balance!
Here's the reasoning:
⓵ A properly balanced chemical equation means that the quantity of atoms on the reactants side matches that on the products side.
→ The equation lacks balance because there are 2 Nitrogen atoms and 2 Hydrogen atoms on the reactants side. In contrast, on the products side, there is only 1 Nitrogen atom and 4 Hydrogen atoms. Thus, the number of atoms on each side is not consistent!
Hopefully, this clarification is helpful; feel free to reach out if you have any further questions! ☻
