In the case of a 100m Race, displacement equals the distance traveled. If we divide this equation by the time t (assuming t represents the time taken to finish the 100m race), we derive that velocity equals speed. Conversely, in a 400m race where a full lap is completed, the racer’s starting and ending positions overlap, leading to displacement equaling 0, while the distance is not zero (400m). Therefore, it follows that displacement does not equal distance, leading to the conclusion that velocity does not equal speed.
Answer: The net ionic equation is 
Explanation:
A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.
The ion-based representation of the equation is:
"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.
Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.
Therefore, the net ionic equation is:
1. Saturated hydrocarbons can either be cyclic or acyclic structures. 2. An unsaturated hydrocarbon molecule contains at least one double bond. Explanation: Greetings, hydrocarbons are defined as the most basic organic compounds comprising only carbon and hydrogen. Therefore, we can eliminate the third statement since ethylenediamine is identified as an amine (an organic structure containing NH groups). Consequently, as saturated hydrocarbons only exhibit single bonds between carbons and carbon-hydrogens, they may be cyclic (ring-shaped) or acyclic (not ring-shaped), establishing the truth of the first statement. Finally, since saturated hydrocarbons exclusively feature single bonds while unsaturated hydrocarbons can exhibit double or triple bonds between carbons and carbon-hydrogens, the existence of at least one double bond categorizes the hydrocarbon as unsaturated. Hence, the first two statements are correct. Best regards.
Fe 3+ + SCN- --> FeSCN 2+
<span>.......Fe 3+.......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>
<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>therefore, according to the calculated Keq, all of the SCN- and Fe 3+ would be fully converted into FeSCN 2+</span>
