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Alexxx
1 month ago
12

Krystal gets paid $750 every two weeks. She wants to save money for next month's rent but she also needs clothes. Does Krystal h

ave enough money left over for clothes and savings for rent?
Mathematics
2 answers:
lawyer [12.5K]1 month ago
6 0

Answer:

How much is the rent? And how many clothes does she want to buy?

Step-by-step explanation:

AnnZ [12.3K]1 month ago
4 0

Answer:

Indeed, she has $330 remaining.

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How many subsets are there in (a,b,c,d,e,f,h,i)?​
Inessa [12570]
The set encompasses 256 subsets. Step-by-step explanation: The elements in the set [a,b,c,d,e,f,h,i] total to 8. The total number of subsets is obtained using the formula

, where n signifies count of elements.

7 0
17 days ago
Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample
lawyer [12517]

Answer:

\mu_{\bar x} = \mu = E(X) =30KWh

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

Step-by-step explanation:

Previous concepts

Normal distribution, is defined as a symmetric "probability distribution centered around the mean, indicating that values near the mean are more common than those further away".

The Z-score measures a value's relation to the mean of a set of values, displayed in terms of how many standard deviations away it is from that mean.

According to the central limit theorem, "with a population having mean μ and standard deviation σ, if we draw sufficient random samples from this population with replacement, the means of those samples will resemble a normal distribution, regardless of the original population's shape, as long as the sample size is large enough".

Solution to the problem

In this scenario, we select a sample size of n = 100

The central limit theorem informs us that the distribution of the sample mean \bar X is defined by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Thus, the mean for the sample would be:

\mu_{\bar x} = \mu = E(X) =30KWh

And the standard deviation would be:

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

6 0
1 month ago
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Leona [12618]
(a) The likelihood that all 5 eggs chosen are unspoiled is 0.0531. (b) The probability that 2 or fewer out of the 5 eggs are unspoiled is 0.3959. (c) The probability that more than 1 of the selected 5 eggs are unspoiled is 0.8747. Step-by-step explanation: The complete query is: A subpar carton of 18 eggs has 8 that are spoiled. An unsuspecting chef selects 5 eggs at random for his “Mega-Omelet Surprise.” Calculate the probability of receiving (a) exactly 5 unspoiled eggs, (b) 2 or fewer, and (c) more than 1 unspoiled egg. Define X = number of unspoiled eggs. In the faulty carton, 8 eggs are spoiled. The probability of selecting an unspoiled egg is independent of others. Provided that a chef randomly picks 5 eggs, the variable X follows a Binomial distribution with parameters n = 5 and p = 0.556. Success is defined as selecting an unspoiled egg. The probability mass function of X is as follows: (a) Calculate the probability of selecting all unspoiled eggs. Thus, this probability is found to be 0.0531. (b) For 2 or less unspoiled eggs, the probability is computed: P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2), resulting in a probability of 0.3959. (c) For more than 1 unspoiled egg: P (X > 1) = 1 - P (X ≤ 1), yields a final probability of 0.8747.
6 0
28 days ago
Kirk and his family decide it is more reasonable for him to attend the local community college. they want to save for the cost o
tester [12383]
To identify the most sensible savings goal for Kirk and his family, follow these calculations:

a. $225 per month over 2 years equals $5400 (calculated as 225 * 2 * 12)
b. $200 per month for 3 years totals $7200 (calculated as 200 * 3 * 12)
c. $100 per month across 4 years will give $4800 (calculated as 100 * 4 * 12)
d. $75 saved monthly for 5 years amounts to $4500 (calculated as 75 * 5 * 12)

The optimal savings target would be option b, since $7200 exceeds <span>$6845.</span>
3 0
1 month ago
Read 2 more answers
Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
PIT_PIT [12445]

Answer:

0.0359

Step-by-step explanation:

Provided values:

Mean durations of three independent processes are 15, 30, and 20 minutes.

The associated standard deviations are 2, 1, and 1.6 minutes, respectively.

Thus,

New Mean = 15 + 30 + 25 = 65

Variance = (standard deviation)²

or

Variance = 2² + 1² + 1.6² = 7.56

<phence>

Standard deviation = √variance

or

Standard deviation = 2.75

<pas a="" result="">

Z-value = \frac{\textup{60 - 65}}{\textup{2.75}}

or

Z-value = - 1.81

Consulting the Z-table, the Probability of Z ≤ -1.81 is equal to 0.0359.

</pas></phence>
6 0
1 month ago
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