The top-level domain (TLD) is the highest level in the domain name system (DNS) hierarchy. In the context of the Internet's DNS, the TLD is operationally positioned within the root zone of the namespace. Generally,.com is regarded as the premier choice, followed closely by.net and.org. For a website tailored for mobile optimization,.com would be the most suitable option.
Options :
The domain name is already taken.
Domain names are required to end with ".com".
You do not hold legal ownership of ABC Company.
Domain names must exclusively use lowercase letters.
Answer:
The domain name is already taken.
Explanation: In the above scenario, ABCcompany.org signifies the domain associated with a specific individual or organization that leads to the owner's website. Each domain name must be unique; therefore, no two different entities or individuals can have identical domain names. Domains can have endings like .com, .org, .ng, and more, and they are not case-sensitive. Thus, the inability to register the mentioned domain is probably because it has already been claimed by someone else.
Answer:
Below is the Python code with suitable comments.
Explanation:
#Input file name acquisition
filename=input('Enter the input file name: ')
#Opening the input file
inputFile = open(filename,"r+")
#Dictionary definition.
list={}
#Read and split file content using a loop
for word in inputFile.read().split():
#Check if the word exists in the file.
if word not in list:
list[word] = 1
#Increment count by 1
else:
list[word] += 1
#Closing the file.
inputFile.close();
#Output a blank line
print();
#Sorting words according to their ASCII values.
for i in sorted(list):
#Display unique words along with their
#frequencies in alphabetical order.
print("{0} {1} ".format(i, list[i]));
Reasoning:
Let's denote the size of a large server as L and the size of a smaller server as S.
According to the data provided, we have two equations:
2L + 4S = 64.............(1)
and
L + 3S = 40...............(2)
To solve the equations, we proceed as follows:
2(2)-(1)
2L - 2L + 6S - 4S = 2*40 - 64
2S = 16
thus, S = 8..................(3), which indicates the size of the small server
Using (3) in (2) yields
L + 3(8) = 40
L = 40 - 24 = 16..............indicating the size of the large server
