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patriot
7 days ago
6

A 5 1/2 quart pot is filled 2/3 of the way with water. How many more quarts of water can the pot hold?

Mathematics
2 answers:
Inessa [3.9K]7 days ago
8 0

The pot has the capability to hold 1/3 more than its current level. Therefore, 1/3 of 5 1/2 quarts equals:

(1/3)(11/2) = 11/6 quarts. Thus, the total capacity of the pot is 11/6 quarts.

lawyer [4K]7 days ago
3 0

Response:

Water needed to fill the pot =\frac{11}{6}\texttt{ quarts}

Detailed explanation:

Capacity of the pot = 5\frac{1}{2} = \frac{11}{2} quart

Proportion of the pot currently filled with water = \frac{2}{3}

Proportion of the pot that is empty = \frac{1}{3}

The additional quarts of water that the pot can accommodate are noted below

          Amount of quarts =\frac{1}{3}\times \frac{11}{2}=\frac{11}{6}\texttt{ quarts}

      Water needed to complete filling the pot =\frac{11}{6}\texttt{ quarts}

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Sarah and her children went into a movie theater and she bought $35.50 worth of drinks and candies. Each drink costs $5 and each
AnnZ [3877]

Answer:

Sarah purchased 2 drinks and 6 candies.

Step-by-step explanation:

Let

x ----> the quantity of drinks Sarah bought.

y ----> the number of candies acquired by Sarah.

We know that

the total spent on drinks and candies was $35.50

therefore,

5x+4.25y=35.50 -----> equation A

She bought 3 times more candies compared to drinks.

thus,

y=3x -----> equation B

To resolve the equations graphically

The solution lies at the intersection of the two graphs

utilizing a graphing tool

The result is the coordinate (2,6)

therefore,

Sarah bought 2 drinks and 6 candies.

4 0
5 days ago
What's the verbal expression for the algebraic expression 1/8y .?
Leona [4166]
The given expression is \frac{1}{8}y

Thus, in verbal form, we can express it as one eighth of a number.


5 0
3 days ago
A follow-up study will be conducted with a sample of 20 people from the 300 people who responded yes (support) and no (do not su
PIT_PIT [3919]

Response:

Detailed explanation:

Hello!

Stratified sampling involves the categorization of the population into subgroups based on pre-established criteria for the study. These subgroups consist of homogeneous units concerning the relevant characteristics. In this instance, individuals in the groups will represent only one of the two potential opinions (support or not support) and not both.

The researcher determines the sample size desired, considering several factors such as finances, material availability, and accessibility to experimental subjects (for instance, if they are endangered species, larger sample sizes may not be feasible).

One might conduct proportionate stratified sampling by selecting a proportion of respondents who answered "yes" along with those who answered "no."

In this sampling method, taking a specific proportion from each subgroup allows for a more straightforward extrapolation of results to the overall populations. For example, if you needed a sample size of n = 20, each stratum would ideally contain half, meaning 10 from the “yes” group and 10 from the “no” group.

I hope this is helpful!

4 0
9 days ago
Two parallel lines are crossed by a transversal. Parallel lines x and y are cut by transversal w. On line x where it intersects
AnnZ [3877]

Answer:

118.2°

Step-by-step explanation:

Dos líneas paralelas x e y son cortadas por la transversal w (ver el diagrama adjunto).

Se forman 8 ángulos (denominados 1, 2, 3, 4, 5, 6, 7 y 8).

Los ángulos 1 y 6 son ángulos del mismo lado cuando dos líneas paralelas x e y son cortadas por la transversal w.

Dos ángulos del mismo lado son suplementarios (suman 180°). Esto significa

m\angle 1+m\angle 6=180^{\circ}

Dado m\angle 1=61.8^{\circ}, por lo que

m\angle 6=180^{\circ}-61.8^{\circ}=118.2^{\circ}

8 0
4 days ago
Read 2 more answers
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
Leona [4166]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • g: gravitational acceleration
  • vo: initial velocity
  • h0: starting height

For the first individual:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second individual:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

When both individuals reach the identical altitude, the following holds:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rearranging results in:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Solving for time:

t = 29 (\frac {12} {19})\\t = 18.31s

Result:

The two window washers reach the same height after 18.31 seconds.

6 0
16 days ago
Read 2 more answers
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