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Alexxandr
2 months ago
6

The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 and a standard deviation of 5,00

0 miles. What is the probability that a randomly selected tire will have a life of exactly 47,500 miles
Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
6 0

Answer: the likelihood of a randomly selected tire lasting exactly 47,500 miles is 0.067

Step-by-step explanation:

Since the expected lifespan of this tire brand follows a normal distribution, we will use the normal distribution formula:

z = (x - µ)/σ

Where

x = lifespan of the tire in miles.

µ = mean

σ = standard deviation

The given figures include,

µ = 40000 miles

σ = 5000 miles

The probability that a tire will last precisely 47,500 miles

P(x = 47500)

For x = 47500,

z = (40000 - 47500) / 5000 = -1.5

According to the standard normal distribution table, the probability associated with this z score is 0.067

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Square T was translated by the rule (x + 2, y + 2) and then dilated from the origin by a scale factor of 3 to create square T″.
AnnZ [12381]

Answer: OPTION C.

Step-by-step explanation:

It is essential to consider the following:

Dilation:

  • A transformation where the image retains the same shape as the original but differs in size.
  • Dilation maintains the order of points.
  •  Measurements of angles remain unchanged.

Translation:

  • A transformation that keeps the image identical in size and shape to the original.
  • Translation preserves the ordering of points.
  • The angle measurements do not change.

Consequently, since Square T underwent translation followed by dilation to form Square T'', we conclude that the rationale explaining why they are similar is:

Translations and dilations maintain the order of points; thereby, the corresponding sides of squares T and T″ are proportional.

6 0
2 months ago
Read 2 more answers
The area of the postcard is 24 square inches. What is the width b of the message (in inches)?
Leona [12618]
Area of a rectangle = length x width
For this postcard:
length = 4 in
width = (3+b) in
area = 24 in^2

Substitute into the area formula:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
4 0
3 months ago
The curvature of the Tacoma Narrows Bridge in
tester [12383]

Response:

The width of the arch measures 105 meters

Detailed explanation:

The function that describes the width of the arch is

f(x) = -0.016(x - 52.5)² + 45

where x denotes the horizontal distance from the left end of the arch or the width at its base

f(x) indicates the vertical height of the arch

According to the given quadratic equation, the vertex coordinates of the parabola are (52.5, 45).

The vertex coordinates indicate that

the arch's height is 45 meters

and half the horizontal span from the left end is 52.5 meters

Therefore, the bridge's total width is calculated as 2 times the half span from the left side, which is 2 × 52.5

resulting in 105 meters

Consequently, the bridge's width is 105 meters.

4 0
2 months ago
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